Input interpretation
![N-benzylquininium chloride | molar mass](../image_source/764393e80291b7a2fdc2180ea167292f.png)
N-benzylquininium chloride | molar mass
Result
![Find the molar mass, M, for N-benzylquininium chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_27H_31ClN_2O_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 27 Cl (chlorine) | 1 H (hydrogen) | 31 N (nitrogen) | 2 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 27 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 31 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 27 | 12.011 | 27 × 12.011 = 324.297 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 31 | 1.008 | 31 × 1.008 = 31.248 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 324.297 g/mol + 35.45 g/mol + 31.248 g/mol + 28.014 g/mol + 31.998 g/mol = 451.01 g/mol](../image_source/41d2d69459260b76757531a8c9e1c4ed.png)
Find the molar mass, M, for N-benzylquininium chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_27H_31ClN_2O_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 27 Cl (chlorine) | 1 H (hydrogen) | 31 N (nitrogen) | 2 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 27 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 31 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 27 | 12.011 | 27 × 12.011 = 324.297 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 31 | 1.008 | 31 × 1.008 = 31.248 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 324.297 g/mol + 35.45 g/mol + 31.248 g/mol + 28.014 g/mol + 31.998 g/mol = 451.01 g/mol
Unit conversion
![0.451 kg/mol (kilograms per mole)](../image_source/e0928c556710333c3aa80a733130394a.png)
0.451 kg/mol (kilograms per mole)
Comparisons
![≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/c4e9a508e894ef82c4b255466a44daee.png)
≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/45e58b95cb13a591fd39bd732de5e545.png)
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/60843db36e8f79da65024633425f31f9.png)
≈ 7.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.5×10^-22 grams | 7.5×10^-25 kg (kilograms) | 451 u (unified atomic mass units) | 451 Da (daltons)](../image_source/27adce511174b2e988095775ffa2b9e3.png)
Mass of a molecule m from m = M/N_A: | 7.5×10^-22 grams | 7.5×10^-25 kg (kilograms) | 451 u (unified atomic mass units) | 451 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 451](../image_source/ca925737eef7a5e6afe4a91862cc84b4.png)
Relative molecular mass M_r from M_r = M_u/M: | 451