Input interpretation
![bestatin | molar mass](../image_source/a20bbd85fa13e371c321c88ff6c68a6e.png)
bestatin | molar mass
Result
![Find the molar mass, M, for bestatin: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (CH_3)_2CHCH_2CH[NHCOCH(OH)CH(NH_2)CH_2C_6H_5]CO_2H Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 16 H (hydrogen) | 24 N (nitrogen) | 2 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 16 | 12.011 H (hydrogen) | 24 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 16 | 12.011 | 16 × 12.011 = 192.176 H (hydrogen) | 24 | 1.008 | 24 × 1.008 = 24.192 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 192.176 g/mol + 24.192 g/mol + 28.014 g/mol + 63.996 g/mol = 308.378 g/mol](../image_source/1d9a42014f091f994616bdeb616c72cc.png)
Find the molar mass, M, for bestatin: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (CH_3)_2CHCH_2CH[NHCOCH(OH)CH(NH_2)CH_2C_6H_5]CO_2H Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 16 H (hydrogen) | 24 N (nitrogen) | 2 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 16 | 12.011 H (hydrogen) | 24 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 16 | 12.011 | 16 × 12.011 = 192.176 H (hydrogen) | 24 | 1.008 | 24 × 1.008 = 24.192 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 192.176 g/mol + 24.192 g/mol + 28.014 g/mol + 63.996 g/mol = 308.378 g/mol
Unit conversion
![0.30838 kg/mol (kilograms per mole)](../image_source/7acd737959129a59de2638388207d9bd.png)
0.30838 kg/mol (kilograms per mole)
Comparisons
![≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/83d5748820a663c6593da018901e5f68.png)
≈ 0.43 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/a850e885c32c6d8108c64abaa4b64ea1.png)
≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/3f160a908add24f2d6f206abd1a3b767.png)
≈ 5.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.1×10^-22 grams | 5.1×10^-25 kg (kilograms) | 308 u (unified atomic mass units) | 308 Da (daltons)](../image_source/04529b83216fc98b565fd857e0f4af17.png)
Mass of a molecule m from m = M/N_A: | 5.1×10^-22 grams | 5.1×10^-25 kg (kilograms) | 308 u (unified atomic mass units) | 308 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 308](../image_source/1d19582c5aa3ec86ff82621f16fa4315.png)
Relative molecular mass M_r from M_r = M_u/M: | 308