Input interpretation
water + boron trifluoride ⟶ boric acid + fluoboric acid
Balanced equation
Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, B and F: H: | 2 c_1 = 3 c_3 + c_4 O: | c_1 = 3 c_3 B: | c_2 = c_3 + c_4 F: | 3 c_2 = 4 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 4 c_3 = 1 c_4 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 + 4 ⟶ + 3
Structures
+ ⟶ +
Names
water + boron trifluoride ⟶ boric acid + fluoboric acid
Chemical names and formulas
| water | boron trifluoride | boric acid | fluoboric acid Hill formula | H_2O | BF_3 | BH_3O_3 | BF_4H name | water | boron trifluoride | boric acid | fluoboric acid IUPAC name | water | trifluoroborane | boric acid | hydrogen(+1) cation; tetrafluoroboron