Input interpretation
silver(I) selenate | molar mass
Result
Find the molar mass, M, for silver(I) selenate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Ag_2SeO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ag (silver) | 2 O (oxygen) | 4 Se (selenium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ag (silver) | 2 | 107.8682 O (oxygen) | 4 | 15.999 Se (selenium) | 1 | 78.971 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ag (silver) | 2 | 107.8682 | 2 × 107.8682 = 215.7364 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Se (selenium) | 1 | 78.971 | 1 × 78.971 = 78.971 M = 215.7364 g/mol + 63.996 g/mol + 78.971 g/mol = 358.703 g/mol
Unit conversion
0.3587 kg/mol (kilograms per mole)
Comparisons
≈ 0.5 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 6.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 6×10^-22 grams | 6×10^-25 kg (kilograms) | 359 u (unified atomic mass units) | 359 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 359