Input interpretation
![cyhalothrin | molar mass](../image_source/23bebe1eae42fc56dfd77fc412c6771d.png)
cyhalothrin | molar mass
Result
![Find the molar mass, M, for cyhalothrin: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_23H_19ClF_3NO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 23 Cl (chlorine) | 1 F (fluorine) | 3 H (hydrogen) | 19 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 23 | 12.011 Cl (chlorine) | 1 | 35.45 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 19 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 23 | 12.011 | 23 × 12.011 = 276.253 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 19 | 1.008 | 19 × 1.008 = 19.152 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 276.253 g/mol + 35.45 g/mol + 56.995209489 g/mol + 19.152 g/mol + 14.007 g/mol + 47.997 g/mol = 449.85 g/mol](../image_source/7684612bbbf3752dc6044efae0087688.png)
Find the molar mass, M, for cyhalothrin: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_23H_19ClF_3NO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 23 Cl (chlorine) | 1 F (fluorine) | 3 H (hydrogen) | 19 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 23 | 12.011 Cl (chlorine) | 1 | 35.45 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 19 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 23 | 12.011 | 23 × 12.011 = 276.253 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 19 | 1.008 | 19 × 1.008 = 19.152 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 276.253 g/mol + 35.45 g/mol + 56.995209489 g/mol + 19.152 g/mol + 14.007 g/mol + 47.997 g/mol = 449.85 g/mol
Unit conversion
![0.44985 kg/mol (kilograms per mole)](../image_source/c69b3d856e5687d2d6d869c8a9f5cb30.png)
0.44985 kg/mol (kilograms per mole)
Comparisons
![≈ 0.62 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/77eab8f5209f65483483bf0fb9ab5bf6.png)
≈ 0.62 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/389ad40306a85e573ed09605cb5ffb24.png)
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/66ae245dee7b7a2d2df29f9ff2032036.png)
≈ 7.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.5×10^-22 grams | 7.5×10^-25 kg (kilograms) | 450 u (unified atomic mass units) | 450 Da (daltons)](../image_source/0eb0c05fbd67a5734722c0e08828c6fc.png)
Mass of a molecule m from m = M/N_A: | 7.5×10^-22 grams | 7.5×10^-25 kg (kilograms) | 450 u (unified atomic mass units) | 450 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 450](../image_source/5f2a2908bb812aa2f9b64cb066e7521e.png)
Relative molecular mass M_r from M_r = M_u/M: | 450