Input interpretation
![bromochlorodifluoromethane | molar mass](../image_source/df5fae8c2a2655a1713ea2e8914ef99c.png)
bromochlorodifluoromethane | molar mass
Result
![Find the molar mass, M, for bromochlorodifluoromethane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CBrClF_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 1 Cl (chlorine) | 1 F (fluorine) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 1 | 12.011 Cl (chlorine) | 1 | 35.45 F (fluorine) | 2 | 18.998403163 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 M = 79.904 g/mol + 12.011 g/mol + 35.45 g/mol + 37.996806326 g/mol = 165.36 g/mol](../image_source/a357ea96c443e18c0cf3b648ad0e17e4.png)
Find the molar mass, M, for bromochlorodifluoromethane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CBrClF_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 1 Cl (chlorine) | 1 F (fluorine) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 1 | 12.011 Cl (chlorine) | 1 | 35.45 F (fluorine) | 2 | 18.998403163 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 M = 79.904 g/mol + 12.011 g/mol + 35.45 g/mol + 37.996806326 g/mol = 165.36 g/mol
Unit conversion
![0.16536 kg/mol (kilograms per mole)](../image_source/fdbee6fc4c74462cefe673c289e73932.png)
0.16536 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/a72fb119a6489ec87d7aa94823edda92.png)
≈ ( 0.23 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.85 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/ffdb6e99c602c393d84104dae7ff9898.png)
≈ 0.85 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/e90739ba45b348f7e2bb813675ba05b2.png)
≈ 2.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 165 u (unified atomic mass units) | 165 Da (daltons)](../image_source/c487623233b1bed48116c610e3825794.png)
Mass of a molecule m from m = M/N_A: | 2.7×10^-22 grams | 2.7×10^-25 kg (kilograms) | 165 u (unified atomic mass units) | 165 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 165](../image_source/dcd751d26f9e42ee29a2a73711da4f56.png)
Relative molecular mass M_r from M_r = M_u/M: | 165