NaNO3 = O2 + NaNO

NaNO_3 (sodium nitrate) ⟶ O_2 (oxygen) + NaNO

Balance the chemical equation algebraically: NaNO_3 ⟶ O_2 + NaNO Add stoichiometric coefficients, c_i, to the reactants and products: c_1 NaNO_3 ⟶ c_2 O_2 + c_3 NaNO Set the number of atoms in the reactants equal to the number of atoms in the products for N, Na and O: N: | c_1 = c_3 Na: | c_1 = c_3 O: | 3 c_1 = 2 c_2 + c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | NaNO_3 ⟶ O_2 + NaNO

⟶ + NaNO

sodium nitrate ⟶ oxygen + NaNO

Construct the equilibrium constant, K, expression for: NaNO_3 ⟶ O_2 + NaNO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: NaNO_3 ⟶ O_2 + NaNO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaNO_3 | 1 | -1 O_2 | 1 | 1 NaNO | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression NaNO_3 | 1 | -1 | ([NaNO3])^(-1) O_2 | 1 | 1 | [O2] NaNO | 1 | 1 | [NaNO] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([NaNO3])^(-1) [O2] [NaNO] = ([O2] [NaNO])/([NaNO3])

Construct the rate of reaction expression for: NaNO_3 ⟶ O_2 + NaNO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: NaNO_3 ⟶ O_2 + NaNO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i NaNO_3 | 1 | -1 O_2 | 1 | 1 NaNO | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term NaNO_3 | 1 | -1 | -(Δ[NaNO3])/(Δt) O_2 | 1 | 1 | (Δ[O2])/(Δt) NaNO | 1 | 1 | (Δ[NaNO])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[NaNO3])/(Δt) = (Δ[O2])/(Δt) = (Δ[NaNO])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| sodium nitrate | oxygen | NaNO formula | NaNO_3 | O_2 | NaNO Hill formula | NNaO_3 | O_2 | NNaO name | sodium nitrate | oxygen | IUPAC name | sodium nitrate | molecular oxygen |

| sodium nitrate | oxygen | NaNO molar mass | 84.994 g/mol | 31.998 g/mol | 52.996 g/mol phase | solid (at STP) | gas (at STP) | melting point | 306 °C | -218 °C | boiling point | | -183 °C | density | 2.26 g/cm^3 | 0.001429 g/cm^3 (at 0 °C) | solubility in water | soluble | | surface tension | | 0.01347 N/m | dynamic viscosity | 0.003 Pa s (at 250 °C) | 2.055×10^-5 Pa s (at 25 °C) | odor | | odorless |