Input interpretation
![1, 2-propanediol dibenzoate | molar mass](../image_source/048cb388f93a44e42c9fe1dbd6cdeb82.png)
1, 2-propanediol dibenzoate | molar mass
Result
![Find the molar mass, M, for 1, 2-propanediol dibenzoate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CO_2CH_2CH(CH_3)O_2CC_6H_5 Use the chemical formula, C_6H_5CO_2CH_2CH(CH_3)O_2CC_6H_5, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 17 H (hydrogen) | 16 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 17 | 12.011 H (hydrogen) | 16 | 1.008 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 17 | 12.011 | 17 × 12.011 = 204.187 H (hydrogen) | 16 | 1.008 | 16 × 1.008 = 16.128 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 204.187 g/mol + 16.128 g/mol + 63.996 g/mol = 284.311 g/mol](../image_source/f10032c4586f1978b597eccb866343fa.png)
Find the molar mass, M, for 1, 2-propanediol dibenzoate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5CO_2CH_2CH(CH_3)O_2CC_6H_5 Use the chemical formula, C_6H_5CO_2CH_2CH(CH_3)O_2CC_6H_5, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 17 H (hydrogen) | 16 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 17 | 12.011 H (hydrogen) | 16 | 1.008 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 17 | 12.011 | 17 × 12.011 = 204.187 H (hydrogen) | 16 | 1.008 | 16 × 1.008 = 16.128 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 204.187 g/mol + 16.128 g/mol + 63.996 g/mol = 284.311 g/mol
Unit conversion
![0.28431 kg/mol (kilograms per mole)](../image_source/9d38752f94ad8982f35edcd0ff7e1ed8.png)
0.28431 kg/mol (kilograms per mole)
Comparisons
![≈ 0.39 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/b81115ffbb7e1de03e727096c4f4f02e.png)
≈ 0.39 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/9d6a6b48085845a5ec2f15afd6687f7a.png)
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/39b7581403e4eca82e656108cc6efdf9.png)
≈ 4.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.7×10^-22 grams | 4.7×10^-25 kg (kilograms) | 284 u (unified atomic mass units) | 284 Da (daltons)](../image_source/afd3b7be449a0d7475c5ef85a717b5a4.png)
Mass of a molecule m from m = M/N_A: | 4.7×10^-22 grams | 4.7×10^-25 kg (kilograms) | 284 u (unified atomic mass units) | 284 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 284](../image_source/d513e6996c92d257387244ed1b7b07d5.png)
Relative molecular mass M_r from M_r = M_u/M: | 284