Input interpretation
periodic acid ⟶ water + HIO4
Balanced equation
Balance the chemical equation algebraically: ⟶ + HIO4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 ⟶ c_2 + c_3 HIO4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, I and O: H: | 5 c_1 = 2 c_2 + c_3 I: | c_1 = c_3 O: | 6 c_1 = c_2 + 4 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | ⟶ 2 + HIO4
Structures
⟶ + HIO4
Names
periodic acid ⟶ water + HIO4
Chemical names and formulas
| periodic acid | water | HIO4 formula | | | HIO4 Hill formula | H_5IO_6 | H_2O | HIO4 name | periodic acid | water |
Substance properties
| periodic acid | water | HIO4 molar mass | 227.94 g/mol | 18.015 g/mol | 191.91 g/mol phase | solid (at STP) | liquid (at STP) | melting point | 122 °C | 0 °C | boiling point | | 99.9839 °C | density | 1.3875 g/cm^3 | 1 g/cm^3 | solubility in water | soluble | | surface tension | | 0.0728 N/m | dynamic viscosity | | 8.9×10^-4 Pa s (at 25 °C) | odor | odorless | odorless |
Units
