Input interpretation
nitrogen triiodide
Chemical names and formulas
formula | I_3N name | nitrogen triiodide alternate names | nitrogen iodide mass fractions | I (iodine) 96.5% | N (nitrogen) 3.55%
Lewis structure
Draw the Lewis structure of nitrogen triiodide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the iodine (n_I, val = 7) and nitrogen (n_N, val = 5) atoms: 3 n_I, val + n_N, val = 26 Calculate the number of electrons needed to completely fill the valence shells for iodine (n_I, full = 8) and nitrogen (n_N, full = 8): 3 n_I, full + n_N, full = 32 Subtracting these two numbers shows that 32 - 26 = 6 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 3 bonds and hence 6 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 26 - 6 = 20 electrons left to draw: Answer: | |
3D structure
3D structure
Basic properties
molar mass | 394.72 g/mol solubility in water | insoluble
Units
Chemical identifiers
CAS number | 13444-85-4 PubChem CID number | 61603 SMILES identifier | N(I)(I)I InChI identifier | InChI=1/I3N/c1-4(2)3 Gmelin number | 164354