Input interpretation
americium(III) iodide | molar mass
Result
Find the molar mass, M, for americium(III) iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: AmI_3 Use the chemical formula, AmI_3, to count the number of atoms, N_i, for each element: | N_i Am (americium) | 1 I (iodine) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Am (americium) | 1 | 243 I (iodine) | 3 | 126.90447 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Am (americium) | 1 | 243 | 1 × 243 = 243 I (iodine) | 3 | 126.90447 | 3 × 126.90447 = 380.71341 M = 243 g/mol + 380.71341 g/mol = 624 g/mol
Unit conversion
0.624 kg/mol (kilograms per mole)
Comparisons
≈ 0.87 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 3.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 11 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 1×10^-21 grams | 1×10^-24 kg (kilograms) | 624 u (unified atomic mass units) | 624 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 624