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Cu + H3PO4 = H2 + Cu3(PO4)2

Input interpretation

Cu copper + H_3PO_4 phosphoric acid ⟶ H_2 hydrogen + Cu_3(PO_4)_2 copper(II) phosphate
Cu copper + H_3PO_4 phosphoric acid ⟶ H_2 hydrogen + Cu_3(PO_4)_2 copper(II) phosphate

Balanced equation

Balance the chemical equation algebraically: Cu + H_3PO_4 ⟶ H_2 + Cu_3(PO_4)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cu + c_2 H_3PO_4 ⟶ c_3 H_2 + c_4 Cu_3(PO_4)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cu, H, O and P: Cu: | c_1 = 3 c_4 H: | 3 c_2 = 2 c_3 O: | 4 c_2 = 8 c_4 P: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 2 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 3 Cu + 2 H_3PO_4 ⟶ 3 H_2 + Cu_3(PO_4)_2
Balance the chemical equation algebraically: Cu + H_3PO_4 ⟶ H_2 + Cu_3(PO_4)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cu + c_2 H_3PO_4 ⟶ c_3 H_2 + c_4 Cu_3(PO_4)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cu, H, O and P: Cu: | c_1 = 3 c_4 H: | 3 c_2 = 2 c_3 O: | 4 c_2 = 8 c_4 P: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 2 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 Cu + 2 H_3PO_4 ⟶ 3 H_2 + Cu_3(PO_4)_2

Structures

 + ⟶ +
+ ⟶ +

Names

copper + phosphoric acid ⟶ hydrogen + copper(II) phosphate
copper + phosphoric acid ⟶ hydrogen + copper(II) phosphate

Equilibrium constant

Construct the equilibrium constant, K, expression for: Cu + H_3PO_4 ⟶ H_2 + Cu_3(PO_4)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 Cu + 2 H_3PO_4 ⟶ 3 H_2 + Cu_3(PO_4)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cu | 3 | -3 H_3PO_4 | 2 | -2 H_2 | 3 | 3 Cu_3(PO_4)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cu | 3 | -3 | ([Cu])^(-3) H_3PO_4 | 2 | -2 | ([H3PO4])^(-2) H_2 | 3 | 3 | ([H2])^3 Cu_3(PO_4)_2 | 1 | 1 | [Cu3(PO4)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([Cu])^(-3) ([H3PO4])^(-2) ([H2])^3 [Cu3(PO4)2] = (([H2])^3 [Cu3(PO4)2])/(([Cu])^3 ([H3PO4])^2)
Construct the equilibrium constant, K, expression for: Cu + H_3PO_4 ⟶ H_2 + Cu_3(PO_4)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 Cu + 2 H_3PO_4 ⟶ 3 H_2 + Cu_3(PO_4)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cu | 3 | -3 H_3PO_4 | 2 | -2 H_2 | 3 | 3 Cu_3(PO_4)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cu | 3 | -3 | ([Cu])^(-3) H_3PO_4 | 2 | -2 | ([H3PO4])^(-2) H_2 | 3 | 3 | ([H2])^3 Cu_3(PO_4)_2 | 1 | 1 | [Cu3(PO4)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cu])^(-3) ([H3PO4])^(-2) ([H2])^3 [Cu3(PO4)2] = (([H2])^3 [Cu3(PO4)2])/(([Cu])^3 ([H3PO4])^2)

Rate of reaction

Construct the rate of reaction expression for: Cu + H_3PO_4 ⟶ H_2 + Cu_3(PO_4)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 Cu + 2 H_3PO_4 ⟶ 3 H_2 + Cu_3(PO_4)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cu | 3 | -3 H_3PO_4 | 2 | -2 H_2 | 3 | 3 Cu_3(PO_4)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cu | 3 | -3 | -1/3 (Δ[Cu])/(Δt) H_3PO_4 | 2 | -2 | -1/2 (Δ[H3PO4])/(Δt) H_2 | 3 | 3 | 1/3 (Δ[H2])/(Δt) Cu_3(PO_4)_2 | 1 | 1 | (Δ[Cu3(PO4)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/3 (Δ[Cu])/(Δt) = -1/2 (Δ[H3PO4])/(Δt) = 1/3 (Δ[H2])/(Δt) = (Δ[Cu3(PO4)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: Cu + H_3PO_4 ⟶ H_2 + Cu_3(PO_4)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 Cu + 2 H_3PO_4 ⟶ 3 H_2 + Cu_3(PO_4)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cu | 3 | -3 H_3PO_4 | 2 | -2 H_2 | 3 | 3 Cu_3(PO_4)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cu | 3 | -3 | -1/3 (Δ[Cu])/(Δt) H_3PO_4 | 2 | -2 | -1/2 (Δ[H3PO4])/(Δt) H_2 | 3 | 3 | 1/3 (Δ[H2])/(Δt) Cu_3(PO_4)_2 | 1 | 1 | (Δ[Cu3(PO4)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[Cu])/(Δt) = -1/2 (Δ[H3PO4])/(Δt) = 1/3 (Δ[H2])/(Δt) = (Δ[Cu3(PO4)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | copper | phosphoric acid | hydrogen | copper(II) phosphate formula | Cu | H_3PO_4 | H_2 | Cu_3(PO_4)_2 Hill formula | Cu | H_3O_4P | H_2 | Cu_3O_8P_2 name | copper | phosphoric acid | hydrogen | copper(II) phosphate IUPAC name | copper | phosphoric acid | molecular hydrogen | tricopper diphosphate
| copper | phosphoric acid | hydrogen | copper(II) phosphate formula | Cu | H_3PO_4 | H_2 | Cu_3(PO_4)_2 Hill formula | Cu | H_3O_4P | H_2 | Cu_3O_8P_2 name | copper | phosphoric acid | hydrogen | copper(II) phosphate IUPAC name | copper | phosphoric acid | molecular hydrogen | tricopper diphosphate

Substance properties

 | copper | phosphoric acid | hydrogen | copper(II) phosphate molar mass | 63.546 g/mol | 97.994 g/mol | 2.016 g/mol | 380.58 g/mol phase | solid (at STP) | liquid (at STP) | gas (at STP) |  melting point | 1083 °C | 42.4 °C | -259.2 °C |  boiling point | 2567 °C | 158 °C | -252.8 °C |  density | 8.96 g/cm^3 | 1.685 g/cm^3 | 8.99×10^-5 g/cm^3 (at 0 °C) |  solubility in water | insoluble | very soluble | | insoluble dynamic viscosity | | | 8.9×10^-6 Pa s (at 25 °C) |  odor | odorless | odorless | odorless |
| copper | phosphoric acid | hydrogen | copper(II) phosphate molar mass | 63.546 g/mol | 97.994 g/mol | 2.016 g/mol | 380.58 g/mol phase | solid (at STP) | liquid (at STP) | gas (at STP) | melting point | 1083 °C | 42.4 °C | -259.2 °C | boiling point | 2567 °C | 158 °C | -252.8 °C | density | 8.96 g/cm^3 | 1.685 g/cm^3 | 8.99×10^-5 g/cm^3 (at 0 °C) | solubility in water | insoluble | very soluble | | insoluble dynamic viscosity | | | 8.9×10^-6 Pa s (at 25 °C) | odor | odorless | odorless | odorless |

Units