Search

HBr + Zn(OH)2 = H2O + ZnBr2

Input interpretation

HBr hydrogen bromide + Zn(OH)_2 zinc hydroxide ⟶ H_2O water + ZnBr_2 zinc bromide
HBr hydrogen bromide + Zn(OH)_2 zinc hydroxide ⟶ H_2O water + ZnBr_2 zinc bromide

Balanced equation

Balance the chemical equation algebraically: HBr + Zn(OH)_2 ⟶ H_2O + ZnBr_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HBr + c_2 Zn(OH)_2 ⟶ c_3 H_2O + c_4 ZnBr_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Br, H, O and Zn: Br: | c_1 = 2 c_4 H: | c_1 + 2 c_2 = 2 c_3 O: | 2 c_2 = c_3 Zn: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HBr + Zn(OH)_2 ⟶ 2 H_2O + ZnBr_2
Balance the chemical equation algebraically: HBr + Zn(OH)_2 ⟶ H_2O + ZnBr_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HBr + c_2 Zn(OH)_2 ⟶ c_3 H_2O + c_4 ZnBr_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Br, H, O and Zn: Br: | c_1 = 2 c_4 H: | c_1 + 2 c_2 = 2 c_3 O: | 2 c_2 = c_3 Zn: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HBr + Zn(OH)_2 ⟶ 2 H_2O + ZnBr_2

Structures

+ ⟶ +
+ ⟶ +

Names

hydrogen bromide + zinc hydroxide ⟶ water + zinc bromide
hydrogen bromide + zinc hydroxide ⟶ water + zinc bromide

Equilibrium constant

Construct the equilibrium constant, K, expression for: HBr + Zn(OH)_2 ⟶ H_2O + ZnBr_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HBr + Zn(OH)_2 ⟶ 2 H_2O + ZnBr_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HBr | 2 | -2 Zn(OH)_2 | 1 | -1 H_2O | 2 | 2 ZnBr_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HBr | 2 | -2 | ([HBr])^(-2) Zn(OH)_2 | 1 | -1 | ([Zn(OH)2])^(-1) H_2O | 2 | 2 | ([H2O])^2 ZnBr_2 | 1 | 1 | [ZnBr2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HBr])^(-2) ([Zn(OH)2])^(-1) ([H2O])^2 [ZnBr2] = (([H2O])^2 [ZnBr2])/(([HBr])^2 [Zn(OH)2])
Construct the equilibrium constant, K, expression for: HBr + Zn(OH)_2 ⟶ H_2O + ZnBr_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HBr + Zn(OH)_2 ⟶ 2 H_2O + ZnBr_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HBr | 2 | -2 Zn(OH)_2 | 1 | -1 H_2O | 2 | 2 ZnBr_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HBr | 2 | -2 | ([HBr])^(-2) Zn(OH)_2 | 1 | -1 | ([Zn(OH)2])^(-1) H_2O | 2 | 2 | ([H2O])^2 ZnBr_2 | 1 | 1 | [ZnBr2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HBr])^(-2) ([Zn(OH)2])^(-1) ([H2O])^2 [ZnBr2] = (([H2O])^2 [ZnBr2])/(([HBr])^2 [Zn(OH)2])

Rate of reaction

Construct the rate of reaction expression for: HBr + Zn(OH)_2 ⟶ H_2O + ZnBr_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HBr + Zn(OH)_2 ⟶ 2 H_2O + ZnBr_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HBr | 2 | -2 Zn(OH)_2 | 1 | -1 H_2O | 2 | 2 ZnBr_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HBr | 2 | -2 | -1/2 (Δ[HBr])/(Δt) Zn(OH)_2 | 1 | -1 | -(Δ[Zn(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) ZnBr_2 | 1 | 1 | (Δ[ZnBr2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[HBr])/(Δt) = -(Δ[Zn(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[ZnBr2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: HBr + Zn(OH)_2 ⟶ H_2O + ZnBr_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HBr + Zn(OH)_2 ⟶ 2 H_2O + ZnBr_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HBr | 2 | -2 Zn(OH)_2 | 1 | -1 H_2O | 2 | 2 ZnBr_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HBr | 2 | -2 | -1/2 (Δ[HBr])/(Δt) Zn(OH)_2 | 1 | -1 | -(Δ[Zn(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) ZnBr_2 | 1 | 1 | (Δ[ZnBr2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[HBr])/(Δt) = -(Δ[Zn(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[ZnBr2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| hydrogen bromide | zinc hydroxide | water | zinc bromide formula | HBr | Zn(OH)_2 | H_2O | ZnBr_2 Hill formula | BrH | H_2O_2Zn | H_2O | Br_2Zn name | hydrogen bromide | zinc hydroxide | water | zinc bromide IUPAC name | hydrogen bromide | zinc dihydroxide | water | dibromozinc
| hydrogen bromide | zinc hydroxide | water | zinc bromide formula | HBr | Zn(OH)_2 | H_2O | ZnBr_2 Hill formula | BrH | H_2O_2Zn | H_2O | Br_2Zn name | hydrogen bromide | zinc hydroxide | water | zinc bromide IUPAC name | hydrogen bromide | zinc dihydroxide | water | dibromozinc

Substance properties

| hydrogen bromide | zinc hydroxide | water | zinc bromide molar mass | 80.912 g/mol | 99.39 g/mol | 18.015 g/mol | 225.2 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -86.8 °C | | 0 °C | 394 °C boiling point | -66.38 °C | | 99.9839 °C | 675 °C density | 0.003307 g/cm^3 (at 25 °C) | | 1 g/cm^3 | 4.22 g/cm^3 solubility in water | miscible | | | surface tension | 0.0271 N/m | | 0.0728 N/m | dynamic viscosity | 8.4×10^-4 Pa s (at -75 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |
| hydrogen bromide | zinc hydroxide | water | zinc bromide molar mass | 80.912 g/mol | 99.39 g/mol | 18.015 g/mol | 225.2 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -86.8 °C | | 0 °C | 394 °C boiling point | -66.38 °C | | 99.9839 °C | 675 °C density | 0.003307 g/cm^3 (at 25 °C) | | 1 g/cm^3 | 4.22 g/cm^3 solubility in water | miscible | | | surface tension | 0.0271 N/m | | 0.0728 N/m | dynamic viscosity | 8.4×10^-4 Pa s (at -75 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units

Random Queries

molar mass of cadmium selenate dihydrate
formulas of Brønsted-Lowry bases
discoverers of non-metallic elements
hydrogen ammonium persulfate
molar mass of ammonium perrhenate vs hydrazine monohydrochloride
DOT numbers of hydrogen bromide vs perchloric acid
find watershed components image sursassite
bond types of carbides
common compound names of scandium vs lutetium
H2 + N2 = NH