Input interpretation
(allyloxycarbonylmethyl)triphenylphosphonium iodide | molar mass
Result
Find the molar mass, M, for (allyloxycarbonylmethyl)triphenylphosphonium iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_6H_5)_3P(CH_2CO_2CH_2CH=CH_2)I Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 23 H (hydrogen) | 22 I (iodine) | 1 O (oxygen) | 2 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 23 | 12.011 H (hydrogen) | 22 | 1.008 I (iodine) | 1 | 126.90447 O (oxygen) | 2 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 23 | 12.011 | 23 × 12.011 = 276.253 H (hydrogen) | 22 | 1.008 | 22 × 1.008 = 22.176 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 276.253 g/mol + 22.176 g/mol + 126.90447 g/mol + 31.998 g/mol + 30.973761998 g/mol = 488.305 g/mol
Unit conversion
0.48831 kg/mol (kilograms per mole)
Comparisons
≈ 0.68 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 8.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 8.1×10^-22 grams | 8.1×10^-25 kg (kilograms) | 488 u (unified atomic mass units) | 488 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 488