mass fractions of lead(II) nitrate

lead(II) nitrate | elemental composition

Find the elemental composition for lead(II) nitrate in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: Pb(NO_3)_2 Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms N (nitrogen) | 2 O (oxygen) | 6 Pb (lead) | 1 N_atoms = 2 + 6 + 1 = 9 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction N (nitrogen) | 2 | 2/9 O (oxygen) | 6 | 6/9 Pb (lead) | 1 | 1/9 Check: 2/9 + 6/9 + 1/9 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent N (nitrogen) | 2 | 2/9 × 100% = 22.2% O (oxygen) | 6 | 6/9 × 100% = 66.7% Pb (lead) | 1 | 1/9 × 100% = 11.1% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u N (nitrogen) | 2 | 22.2% | 14.007 O (oxygen) | 6 | 66.7% | 15.999 Pb (lead) | 1 | 11.1% | 207.2 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u N (nitrogen) | 2 | 22.2% | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 6 | 66.7% | 15.999 | 6 × 15.999 = 95.994 Pb (lead) | 1 | 11.1% | 207.2 | 1 × 207.2 = 207.2 m = 28.014 u + 95.994 u + 207.2 u = 331.208 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction N (nitrogen) | 2 | 22.2% | 28.014/331.208 O (oxygen) | 6 | 66.7% | 95.994/331.208 Pb (lead) | 1 | 11.1% | 207.2/331.208 Check: 28.014/331.208 + 95.994/331.208 + 207.2/331.208 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent N (nitrogen) | 2 | 22.2% | 28.014/331.208 × 100% = 8.458% O (oxygen) | 6 | 66.7% | 95.994/331.208 × 100% = 28.98% Pb (lead) | 1 | 11.1% | 207.2/331.208 × 100% = 62.56%

Mass fraction pie chart