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monofluorophosphoric acid

Input interpretation

monofluorophosphoric acid
monofluorophosphoric acid

Chemical names and formulas

formula | FP(O)(OH)_2 Hill formula | FH_2O_3P name | monofluorophosphoric acid IUPAC name | fluorophosphonic acid alternate names | fluorophosphonic acid | fluorophosphoric acid | fluorophosphoric acid, anhydrous | fluorophosphoric acid (h2PO3F) | phosphorofluoridic acid mass fractions | F (fluorine) 19% | H (hydrogen) 2.02% | O (oxygen) 48% | P (phosphorus) 31%
formula | FP(O)(OH)_2 Hill formula | FH_2O_3P name | monofluorophosphoric acid IUPAC name | fluorophosphonic acid alternate names | fluorophosphonic acid | fluorophosphoric acid | fluorophosphoric acid, anhydrous | fluorophosphoric acid (h2PO3F) | phosphorofluoridic acid mass fractions | F (fluorine) 19% | H (hydrogen) 2.02% | O (oxygen) 48% | P (phosphorus) 31%

Lewis structure

Draw the Lewis structure of monofluorophosphoric acid. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds:  Count the total valence electrons of the fluorine (n_F, val = 7), hydrogen (n_H, val = 1), oxygen (n_O, val = 6), and phosphorus (n_P, val = 5) atoms: n_F, val + 2 n_H, val + 3 n_O, val + n_P, val = 32 Calculate the number of electrons needed to completely fill the valence shells for fluorine (n_F, full = 8), hydrogen (n_H, full = 2), oxygen (n_O, full = 8), and phosphorus (n_P, full = 8): n_F, full + 2 n_H, full + 3 n_O, full + n_P, full = 44 Subtracting these two numbers shows that 44 - 32 = 12 bonding electrons are needed. Each bond has two electrons, so we expect that the above diagram has all the necessary bonds. However, to minimize formal charge oxygen wants 2 bonds. Identify the atom that wants additional bonds and the number of electrons remaining on each atom:  In order to minimize their formal charge, atoms with large electronegativities can force atoms with smaller electronegativities on period 3 or higher to expand their valence shells. The electronegativities of the atoms are 2.19 (phosphorus), 2.20 (hydrogen), 3.44 (oxygen), and 3.98 (fluorine). Because the electronegativity of phosphorus is smaller than the electronegativity of oxygen, expand the valence shell of phosphorus to 5 bonds. Therefore we add a total of 1 bond to the diagram: Answer: |   |
Draw the Lewis structure of monofluorophosphoric acid. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the fluorine (n_F, val = 7), hydrogen (n_H, val = 1), oxygen (n_O, val = 6), and phosphorus (n_P, val = 5) atoms: n_F, val + 2 n_H, val + 3 n_O, val + n_P, val = 32 Calculate the number of electrons needed to completely fill the valence shells for fluorine (n_F, full = 8), hydrogen (n_H, full = 2), oxygen (n_O, full = 8), and phosphorus (n_P, full = 8): n_F, full + 2 n_H, full + 3 n_O, full + n_P, full = 44 Subtracting these two numbers shows that 44 - 32 = 12 bonding electrons are needed. Each bond has two electrons, so we expect that the above diagram has all the necessary bonds. However, to minimize formal charge oxygen wants 2 bonds. Identify the atom that wants additional bonds and the number of electrons remaining on each atom: In order to minimize their formal charge, atoms with large electronegativities can force atoms with smaller electronegativities on period 3 or higher to expand their valence shells. The electronegativities of the atoms are 2.19 (phosphorus), 2.20 (hydrogen), 3.44 (oxygen), and 3.98 (fluorine). Because the electronegativity of phosphorus is smaller than the electronegativity of oxygen, expand the valence shell of phosphorus to 5 bonds. Therefore we add a total of 1 bond to the diagram: Answer: | |

3D structure

3D structure
3D structure

Basic properties

molar mass | 99.985 g/mol phase | liquid (at STP) melting point | -30 °C density | 1.83 g/cm^3 solubility in water | very soluble
molar mass | 99.985 g/mol phase | liquid (at STP) melting point | -30 °C density | 1.83 g/cm^3 solubility in water | very soluble

Units

Liquid properties (at STP)

density | 1.83 g/cm^3
density | 1.83 g/cm^3

Units

Chemical identifiers

CAS number | 13537-32-1 PubChem CID number | 24267 PubChem SID number | 24859463 SMILES identifier | OP(=O)(O)F InChI identifier | InChI=1/FH2O3P/c1-5(2, 3)4/h(H2, 2, 3, 4)/f/h2-3H RTECS number | TE5000000 MDL number | MFCD00011334
CAS number | 13537-32-1 PubChem CID number | 24267 PubChem SID number | 24859463 SMILES identifier | OP(=O)(O)F InChI identifier | InChI=1/FH2O3P/c1-5(2, 3)4/h(H2, 2, 3, 4)/f/h2-3H RTECS number | TE5000000 MDL number | MFCD00011334

NFPA label

NFPA label
NFPA label
NFPA health rating | 3 NFPA fire rating | 0 NFPA reactivity rating | 0
NFPA health rating | 3 NFPA fire rating | 0 NFPA reactivity rating | 0

Toxicity properties

RTECS classes | other
RTECS classes | other