Input interpretation
![2, 3, 7, 8, 12, 13, 17, 18-octaethyl-21H, 23 H-porphine copper(II) | molecular mass](../image_source/13afb8f84cef5af32709fe9b04682315.png)
2, 3, 7, 8, 12, 13, 17, 18-octaethyl-21H, 23 H-porphine copper(II) | molecular mass
Result
![Find the molecular mass, m, for 2, 3, 7, 8, 12, 13, 17, 18-octaethyl-21H, 23 H-porphine copper(II): m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_36H_46CuN_4)^2+ Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cu (copper) | 1 C (carbon) | 36 N (nitrogen) | 4 H (hydrogen) | 46 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u Cu (copper) | 1 | 63.546 C (carbon) | 36 | 12.011 N (nitrogen) | 4 | 14.007 H (hydrogen) | 46 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u Cu (copper) | 1 | 63.546 | 1 × 63.546 = 63.546 C (carbon) | 36 | 12.011 | 36 × 12.011 = 432.396 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 H (hydrogen) | 46 | 1.008 | 46 × 1.008 = 46.368 m = 63.546 u + 432.396 u + 56.028 u + 46.368 u = 598.338 u](../image_source/1b9a364cf72afe0ced5f403dd1dbc285.png)
Find the molecular mass, m, for 2, 3, 7, 8, 12, 13, 17, 18-octaethyl-21H, 23 H-porphine copper(II): m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_36H_46CuN_4)^2+ Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cu (copper) | 1 C (carbon) | 36 N (nitrogen) | 4 H (hydrogen) | 46 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u Cu (copper) | 1 | 63.546 C (carbon) | 36 | 12.011 N (nitrogen) | 4 | 14.007 H (hydrogen) | 46 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u Cu (copper) | 1 | 63.546 | 1 × 63.546 = 63.546 C (carbon) | 36 | 12.011 | 36 × 12.011 = 432.396 N (nitrogen) | 4 | 14.007 | 4 × 14.007 = 56.028 H (hydrogen) | 46 | 1.008 | 46 × 1.008 = 46.368 m = 63.546 u + 432.396 u + 56.028 u + 46.368 u = 598.338 u
Unit conversions
![598.3 Da (daltons)](../image_source/c7f9a5256f0ecac085e4e1284e1ddf34.png)
598.3 Da (daltons)
![0.5983 kDa (kilodaltons)](../image_source/5dd2af955073833760d1861512ebdfc0.png)
0.5983 kDa (kilodaltons)
![9.935×10^-22 grams](../image_source/164433ca3b813d81c1fe0cc21f8661cb.png)
9.935×10^-22 grams
![9.935×10^-25 kg (kilograms)](../image_source/67ca01cfcb4ad8b38ccb73981534d54e.png)
9.935×10^-25 kg (kilograms)
![598.3 chemical atomic mass units (unit officially deprecated)](../image_source/c01a1ec1f3926babad97cd827188fd4d.png)
598.3 chemical atomic mass units (unit officially deprecated)
Comparisons as mass of molecule
![≈ 0.83 × molecular mass of fullerene ( ≈ 721 u )](../image_source/4b015351e14cab912dfc7b3e8b2126f3.png)
≈ 0.83 × molecular mass of fullerene ( ≈ 721 u )
![≈ 3.1 × molecular mass of caffeine ( ≈ 194 u )](../image_source/edf72e60abab9cb12c528fe7e3970066.png)
≈ 3.1 × molecular mass of caffeine ( ≈ 194 u )
![≈ 10 × molecular mass of sodium chloride ( ≈ 58 u )](../image_source/d99f36d0e8993260b2c1cb2e7cfa4ad1.png)
≈ 10 × molecular mass of sodium chloride ( ≈ 58 u )
Corresponding quantities
![Relative atomic mass A_r from A_r = m_aN_A/M_u: | 598](../image_source/94d3fea407fccd1f91c960ba8fe1192f.png)
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 598
![Molar mass M from M = m_aN_A: | 598 g/mol (grams per mole)](../image_source/76efead49efccacb6b8b24589ea26929.png)
Molar mass M from M = m_aN_A: | 598 g/mol (grams per mole)
![Relative molecular mass M_r from M_r = m_mN_A/M_u: | 598](../image_source/3f6a261cd46e1937c8e599d8f6939a58.png)
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 598
![Molar mass M from M = m_mN_A: | 598 g/mol (grams per mole)](../image_source/47dbf2ad4aa7c67b9d9df823ea3e62eb.png)
Molar mass M from M = m_mN_A: | 598 g/mol (grams per mole)