Input interpretation
![5-(1, 3-dioxolan-2-yl)-2-thienylzinc bromide | molar mass](../image_source/a7ac4b8d03bf68fe3793574aad6dc0fe.png)
5-(1, 3-dioxolan-2-yl)-2-thienylzinc bromide | molar mass
Result
![Find the molar mass, M, for 5-(1, 3-dioxolan-2-yl)-2-thienylzinc bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_7H_7BrO_2SZn Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 O (oxygen) | 2 C (carbon) | 7 S (sulfur) | 1 Zn (zinc) | 1 H (hydrogen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 O (oxygen) | 2 | 15.999 C (carbon) | 7 | 12.011 S (sulfur) | 1 | 32.06 Zn (zinc) | 1 | 65.38 H (hydrogen) | 7 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 M = 79.904 g/mol + 31.998 g/mol + 84.077 g/mol + 32.06 g/mol + 65.38 g/mol + 7.056 g/mol = 300.48 g/mol](../image_source/ade16eec698075e94a50f9267376f648.png)
Find the molar mass, M, for 5-(1, 3-dioxolan-2-yl)-2-thienylzinc bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_7H_7BrO_2SZn Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 O (oxygen) | 2 C (carbon) | 7 S (sulfur) | 1 Zn (zinc) | 1 H (hydrogen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 O (oxygen) | 2 | 15.999 C (carbon) | 7 | 12.011 S (sulfur) | 1 | 32.06 Zn (zinc) | 1 | 65.38 H (hydrogen) | 7 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 C (carbon) | 7 | 12.011 | 7 × 12.011 = 84.077 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 H (hydrogen) | 7 | 1.008 | 7 × 1.008 = 7.056 M = 79.904 g/mol + 31.998 g/mol + 84.077 g/mol + 32.06 g/mol + 65.38 g/mol + 7.056 g/mol = 300.48 g/mol
Unit conversion
![0.3005 kg/mol (kilograms per mole)](../image_source/441aeba0ec9cdb3ca83248c83bb2a4a2.png)
0.3005 kg/mol (kilograms per mole)
Comparisons
![≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/42c2df0d16a75ea60bd1b2613319f643.png)
≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/19224a9ba33be32180ea9aacf4551f5c.png)
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/a90eb917d7caca565131a96629cd88a2.png)
≈ 5.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5×10^-22 grams | 5×10^-25 kg (kilograms) | 300 u (unified atomic mass units) | 300 Da (daltons)](../image_source/7f4abcfa9ba055fb9aa791644fd4ada7.png)
Mass of a molecule m from m = M/N_A: | 5×10^-22 grams | 5×10^-25 kg (kilograms) | 300 u (unified atomic mass units) | 300 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 300](../image_source/05207171ce52ea98ab7c5bfab502dd11.png)
Relative molecular mass M_r from M_r = M_u/M: | 300