Input interpretation
![fmoc-(4-iodo)-phe-OH | molar mass](../image_source/d3230ff523615318572a704cb50059ff.png)
fmoc-(4-iodo)-phe-OH | molar mass
Result
![Find the molar mass, M, for fmoc-(4-iodo)-phe-OH: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_24H_20INO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 24 H (hydrogen) | 20 I (iodine) | 1 N (nitrogen) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 24 | 12.011 H (hydrogen) | 20 | 1.008 I (iodine) | 1 | 126.90447 N (nitrogen) | 1 | 14.007 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 24 | 12.011 | 24 × 12.011 = 288.264 H (hydrogen) | 20 | 1.008 | 20 × 1.008 = 20.160 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 288.264 g/mol + 20.160 g/mol + 126.90447 g/mol + 14.007 g/mol + 63.996 g/mol = 513.331 g/mol](../image_source/81ab7351e2765eb0c5ce00ce5c7fd5e0.png)
Find the molar mass, M, for fmoc-(4-iodo)-phe-OH: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_24H_20INO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 24 H (hydrogen) | 20 I (iodine) | 1 N (nitrogen) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 24 | 12.011 H (hydrogen) | 20 | 1.008 I (iodine) | 1 | 126.90447 N (nitrogen) | 1 | 14.007 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 24 | 12.011 | 24 × 12.011 = 288.264 H (hydrogen) | 20 | 1.008 | 20 × 1.008 = 20.160 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 288.264 g/mol + 20.160 g/mol + 126.90447 g/mol + 14.007 g/mol + 63.996 g/mol = 513.331 g/mol
Unit conversion
![0.51333 kg/mol (kilograms per mole)](../image_source/3ce9fdd8ae0b241164a5ea8e713e19de.png)
0.51333 kg/mol (kilograms per mole)
Comparisons
![≈ 0.71 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/42bc977531593f2404b183df5625fd98.png)
≈ 0.71 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.6 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/fe7faeb515fb0d435ff3400315f4d604.png)
≈ 2.6 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 8.8 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/3cdef653ba9e27a0c2a76d7fbbd1ef6a.png)
≈ 8.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 8.5×10^-22 grams | 8.5×10^-25 kg (kilograms) | 513 u (unified atomic mass units) | 513 Da (daltons)](../image_source/2aa4d851a16b1e396af586e6db46967f.png)
Mass of a molecule m from m = M/N_A: | 8.5×10^-22 grams | 8.5×10^-25 kg (kilograms) | 513 u (unified atomic mass units) | 513 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 513](../image_source/5d72391a3fea6716980a36546197ff10.png)
Relative molecular mass M_r from M_r = M_u/M: | 513