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KOH + Zn(NO3)2 = KNO3 + Zn(OH)2

Input interpretation

KOH potassium hydroxide + Zn(NO3)2 ⟶ KNO_3 potassium nitrate + Zn(OH)_2 zinc hydroxide
KOH potassium hydroxide + Zn(NO3)2 ⟶ KNO_3 potassium nitrate + Zn(OH)_2 zinc hydroxide

Balanced equation

Balance the chemical equation algebraically: KOH + Zn(NO3)2 ⟶ KNO_3 + Zn(OH)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 Zn(NO3)2 ⟶ c_3 KNO_3 + c_4 Zn(OH)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Zn and N: H: | c_1 = 2 c_4 K: | c_1 = c_3 O: | c_1 + 6 c_2 = 3 c_3 + 2 c_4 Zn: | c_2 = c_4 N: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 KOH + Zn(NO3)2 ⟶ 2 KNO_3 + Zn(OH)_2
Balance the chemical equation algebraically: KOH + Zn(NO3)2 ⟶ KNO_3 + Zn(OH)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 KOH + c_2 Zn(NO3)2 ⟶ c_3 KNO_3 + c_4 Zn(OH)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, K, O, Zn and N: H: | c_1 = 2 c_4 K: | c_1 = c_3 O: | c_1 + 6 c_2 = 3 c_3 + 2 c_4 Zn: | c_2 = c_4 N: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 KOH + Zn(NO3)2 ⟶ 2 KNO_3 + Zn(OH)_2

Structures

+ Zn(NO3)2 ⟶ +
+ Zn(NO3)2 ⟶ +

Names

potassium hydroxide + Zn(NO3)2 ⟶ potassium nitrate + zinc hydroxide
potassium hydroxide + Zn(NO3)2 ⟶ potassium nitrate + zinc hydroxide

Equilibrium constant

Construct the equilibrium constant, K, expression for: KOH + Zn(NO3)2 ⟶ KNO_3 + Zn(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 KOH + Zn(NO3)2 ⟶ 2 KNO_3 + Zn(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 Zn(NO3)2 | 1 | -1 KNO_3 | 2 | 2 Zn(OH)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 2 | -2 | ([KOH])^(-2) Zn(NO3)2 | 1 | -1 | ([Zn(NO3)2])^(-1) KNO_3 | 2 | 2 | ([KNO3])^2 Zn(OH)_2 | 1 | 1 | [Zn(OH)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-2) ([Zn(NO3)2])^(-1) ([KNO3])^2 [Zn(OH)2] = (([KNO3])^2 [Zn(OH)2])/(([KOH])^2 [Zn(NO3)2])
Construct the equilibrium constant, K, expression for: KOH + Zn(NO3)2 ⟶ KNO_3 + Zn(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 KOH + Zn(NO3)2 ⟶ 2 KNO_3 + Zn(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 Zn(NO3)2 | 1 | -1 KNO_3 | 2 | 2 Zn(OH)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression KOH | 2 | -2 | ([KOH])^(-2) Zn(NO3)2 | 1 | -1 | ([Zn(NO3)2])^(-1) KNO_3 | 2 | 2 | ([KNO3])^2 Zn(OH)_2 | 1 | 1 | [Zn(OH)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([KOH])^(-2) ([Zn(NO3)2])^(-1) ([KNO3])^2 [Zn(OH)2] = (([KNO3])^2 [Zn(OH)2])/(([KOH])^2 [Zn(NO3)2])

Rate of reaction

Construct the rate of reaction expression for: KOH + Zn(NO3)2 ⟶ KNO_3 + Zn(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 KOH + Zn(NO3)2 ⟶ 2 KNO_3 + Zn(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 Zn(NO3)2 | 1 | -1 KNO_3 | 2 | 2 Zn(OH)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 2 | -2 | -1/2 (Δ[KOH])/(Δt) Zn(NO3)2 | 1 | -1 | -(Δ[Zn(NO3)2])/(Δt) KNO_3 | 2 | 2 | 1/2 (Δ[KNO3])/(Δt) Zn(OH)_2 | 1 | 1 | (Δ[Zn(OH)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[KOH])/(Δt) = -(Δ[Zn(NO3)2])/(Δt) = 1/2 (Δ[KNO3])/(Δt) = (Δ[Zn(OH)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: KOH + Zn(NO3)2 ⟶ KNO_3 + Zn(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 KOH + Zn(NO3)2 ⟶ 2 KNO_3 + Zn(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i KOH | 2 | -2 Zn(NO3)2 | 1 | -1 KNO_3 | 2 | 2 Zn(OH)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term KOH | 2 | -2 | -1/2 (Δ[KOH])/(Δt) Zn(NO3)2 | 1 | -1 | -(Δ[Zn(NO3)2])/(Δt) KNO_3 | 2 | 2 | 1/2 (Δ[KNO3])/(Δt) Zn(OH)_2 | 1 | 1 | (Δ[Zn(OH)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[KOH])/(Δt) = -(Δ[Zn(NO3)2])/(Δt) = 1/2 (Δ[KNO3])/(Δt) = (Δ[Zn(OH)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| potassium hydroxide | Zn(NO3)2 | potassium nitrate | zinc hydroxide formula | KOH | Zn(NO3)2 | KNO_3 | Zn(OH)_2 Hill formula | HKO | N2O6Zn | KNO_3 | H_2O_2Zn name | potassium hydroxide | | potassium nitrate | zinc hydroxide IUPAC name | potassium hydroxide | | potassium nitrate | zinc dihydroxide
| potassium hydroxide | Zn(NO3)2 | potassium nitrate | zinc hydroxide formula | KOH | Zn(NO3)2 | KNO_3 | Zn(OH)_2 Hill formula | HKO | N2O6Zn | KNO_3 | H_2O_2Zn name | potassium hydroxide | | potassium nitrate | zinc hydroxide IUPAC name | potassium hydroxide | | potassium nitrate | zinc dihydroxide

Substance properties

| potassium hydroxide | Zn(NO3)2 | potassium nitrate | zinc hydroxide molar mass | 56.105 g/mol | 189.4 g/mol | 101.1 g/mol | 99.39 g/mol phase | solid (at STP) | | solid (at STP) | melting point | 406 °C | | 334 °C | boiling point | 1327 °C | | | density | 2.044 g/cm^3 | | | solubility in water | soluble | | soluble | dynamic viscosity | 0.001 Pa s (at 550 °C) | | | odor | | | odorless |
| potassium hydroxide | Zn(NO3)2 | potassium nitrate | zinc hydroxide molar mass | 56.105 g/mol | 189.4 g/mol | 101.1 g/mol | 99.39 g/mol phase | solid (at STP) | | solid (at STP) | melting point | 406 °C | | 334 °C | boiling point | 1327 °C | | | density | 2.044 g/cm^3 | | | solubility in water | soluble | | soluble | dynamic viscosity | 0.001 Pa s (at 550 °C) | | | odor | | | odorless |

Units

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