HCl + H2S + Na2SO3 = H2O + S + NaCl

HCl hydrogen chloride + H_2S hydrogen sulfide + Na_2SO_3 sodium sulfite ⟶ H_2O water + S mixed sulfur + NaCl sodium chloride

Balance the chemical equation algebraically: HCl + H_2S + Na_2SO_3 ⟶ H_2O + S + NaCl Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HCl + c_2 H_2S + c_3 Na_2SO_3 ⟶ c_4 H_2O + c_5 S + c_6 NaCl Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, S, Na and O: Cl: | c_1 = c_6 H: | c_1 + 2 c_2 = 2 c_4 S: | c_2 + c_3 = c_5 Na: | 2 c_3 = c_6 O: | 3 c_3 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 1 c_4 = 3 c_5 = 3 c_6 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HCl + 2 H_2S + Na_2SO_3 ⟶ 3 H_2O + 3 S + 2 NaCl

+ + ⟶ + +

hydrogen chloride + hydrogen sulfide + sodium sulfite ⟶ water + mixed sulfur + sodium chloride

K_c = ([H2O]^3 [S]^3 [NaCl]^2)/([HCl]^2 [H2S]^2 [Na2SO3])

rate = -1/2 (Δ[HCl])/(Δt) = -1/2 (Δ[H2S])/(Δt) = -(Δ[Na2SO3])/(Δt) = 1/3 (Δ[H2O])/(Δt) = 1/3 (Δ[S])/(Δt) = 1/2 (Δ[NaCl])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| hydrogen chloride | hydrogen sulfide | sodium sulfite | water | mixed sulfur | sodium chloride formula | HCl | H_2S | Na_2SO_3 | H_2O | S | NaCl Hill formula | ClH | H_2S | Na_2O_3S | H_2O | S | ClNa name | hydrogen chloride | hydrogen sulfide | sodium sulfite | water | mixed sulfur | sodium chloride IUPAC name | hydrogen chloride | hydrogen sulfide | disodium sulfite | water | sulfur | sodium chloride