Input interpretation
phosphoric acid ⟶ water + P2O5
Balanced equation
Balance the chemical equation algebraically: ⟶ + P2O5 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 ⟶ c_2 + c_3 P2O5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and P: H: | 3 c_1 = 2 c_2 O: | 4 c_1 = c_2 + 5 c_3 P: | c_1 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 3 c_3 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 ⟶ 3 + P2O5
Structures
⟶ + P2O5
Names
phosphoric acid ⟶ water + P2O5
Chemical names and formulas
| phosphoric acid | water | P2O5 formula | | | P2O5 Hill formula | H_3O_4P | H_2O | O5P2 name | phosphoric acid | water |
Substance properties
| phosphoric acid | water | P2O5 molar mass | 97.994 g/mol | 18.015 g/mol | 141.94 g/mol phase | liquid (at STP) | liquid (at STP) | melting point | 42.4 °C | 0 °C | boiling point | 158 °C | 99.9839 °C | density | 1.685 g/cm^3 | 1 g/cm^3 | solubility in water | very soluble | | surface tension | | 0.0728 N/m | dynamic viscosity | | 8.9×10^-4 Pa s (at 25 °C) | odor | odorless | odorless |
Units
