Input interpretation
![3-(trifluoromethoxy)benzonitrile | molar mass](../image_source/c17fca70ac046539d4f143e59a95f194.png)
3-(trifluoromethoxy)benzonitrile | molar mass
Result
![Find the molar mass, M, for 3-(trifluoromethoxy)benzonitrile: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_8H_4F_3NO Use the chemical formula, C_8H_4F_3NO, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 F (fluorine) | 3 H (hydrogen) | 4 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 8 | 12.011 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 4 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 96.088 g/mol + 56.995209489 g/mol + 4.032 g/mol + 14.007 g/mol + 15.999 g/mol = 187.121 g/mol](../image_source/c71c9470e886eb1885c1d253d2d1f0aa.png)
Find the molar mass, M, for 3-(trifluoromethoxy)benzonitrile: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_8H_4F_3NO Use the chemical formula, C_8H_4F_3NO, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 F (fluorine) | 3 H (hydrogen) | 4 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 8 | 12.011 F (fluorine) | 3 | 18.998403163 H (hydrogen) | 4 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 96.088 g/mol + 56.995209489 g/mol + 4.032 g/mol + 14.007 g/mol + 15.999 g/mol = 187.121 g/mol
Unit conversion
![0.18712 kg/mol (kilograms per mole)](../image_source/228a1620a0b2d0a0b2e29d8b4836e25d.png)
0.18712 kg/mol (kilograms per mole)
Comparisons
![≈ 0.26 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/8eda7481bf7c319c407373c2607aafd0.png)
≈ 0.26 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.96 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/357e92034f4c499732a1240eb5f15f1f.png)
≈ 0.96 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/3630fe505f6da6efb7b6a24d118df47f.png)
≈ 3.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.1×10^-22 grams | 3.1×10^-25 kg (kilograms) | 187 u (unified atomic mass units) | 187 Da (daltons)](../image_source/23c6b90ea6c71925e9150dc2c3c725b3.png)
Mass of a molecule m from m = M/N_A: | 3.1×10^-22 grams | 3.1×10^-25 kg (kilograms) | 187 u (unified atomic mass units) | 187 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 187](../image_source/50a0c2fa08dd15a2138c239fbb5c4aa8.png)
Relative molecular mass M_r from M_r = M_u/M: | 187