Input interpretation
![ammonium chromate | molar mass](../image_source/3a5b34f01bfa55010703704e6edde283.png)
ammonium chromate | molar mass
Result
![Find the molar mass, M, for ammonium chromate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (NH_4)_2CrO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cr (chromium) | 1 H (hydrogen) | 8 N (nitrogen) | 2 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cr (chromium) | 1 | 51.9961 H (hydrogen) | 8 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 51.9961 g/mol + 8.064 g/mol + 28.014 g/mol + 63.996 g/mol = 152.070 g/mol](../image_source/0ecc18a081ca9e24c2fc8242a61f8a0e.png)
Find the molar mass, M, for ammonium chromate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (NH_4)_2CrO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cr (chromium) | 1 H (hydrogen) | 8 N (nitrogen) | 2 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cr (chromium) | 1 | 51.9961 H (hydrogen) | 8 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 51.9961 g/mol + 8.064 g/mol + 28.014 g/mol + 63.996 g/mol = 152.070 g/mol
Unit conversion
![0.15207 kg/mol (kilograms per mole)](../image_source/90594e41132f1231d88fda72549f7343.png)
0.15207 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.21 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/73c98de69501793afb4125d0a5ee00a6.png)
≈ ( 0.21 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.78 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/03a8b483c0de0e96dc8d4b359a6c2567.png)
≈ 0.78 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.6 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/89d4b0d3b6875919d4b91f662c5f174a.png)
≈ 2.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.5×10^-22 grams | 2.5×10^-25 kg (kilograms) | 152 u (unified atomic mass units) | 152 Da (daltons)](../image_source/f048fbb014fef41d91e9bddc820e9176.png)
Mass of a molecule m from m = M/N_A: | 2.5×10^-22 grams | 2.5×10^-25 kg (kilograms) | 152 u (unified atomic mass units) | 152 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 152](../image_source/d866b23c04d96dafdec7c9e7e7c98c94.png)
Relative molecular mass M_r from M_r = M_u/M: | 152