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Zn + FeCl3 = Fe + ZnCl2

Input interpretation

Zn (zinc) + FeCl_3 (iron(III) chloride) ⟶ Fe (iron) + ZnCl_2 (zinc chloride)
Zn (zinc) + FeCl_3 (iron(III) chloride) ⟶ Fe (iron) + ZnCl_2 (zinc chloride)

Balanced equation

Balance the chemical equation algebraically: Zn + FeCl_3 ⟶ Fe + ZnCl_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Zn + c_2 FeCl_3 ⟶ c_3 Fe + c_4 ZnCl_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Zn, Cl and Fe: Zn: | c_1 = c_4 Cl: | 3 c_2 = 2 c_4 Fe: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 1 c_3 = 1 c_4 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 2 c_3 = 2 c_4 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 3 Zn + 2 FeCl_3 ⟶ 2 Fe + 3 ZnCl_2
Balance the chemical equation algebraically: Zn + FeCl_3 ⟶ Fe + ZnCl_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Zn + c_2 FeCl_3 ⟶ c_3 Fe + c_4 ZnCl_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Zn, Cl and Fe: Zn: | c_1 = c_4 Cl: | 3 c_2 = 2 c_4 Fe: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 1 c_3 = 1 c_4 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 2 c_3 = 2 c_4 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 Zn + 2 FeCl_3 ⟶ 2 Fe + 3 ZnCl_2

Structures

 + ⟶ +
+ ⟶ +

Names

zinc + iron(III) chloride ⟶ iron + zinc chloride
zinc + iron(III) chloride ⟶ iron + zinc chloride

Reaction thermodynamics

Enthalpy

 | zinc | iron(III) chloride | iron | zinc chloride molecular enthalpy | 0 kJ/mol | -399.5 kJ/mol | 0 kJ/mol | -415.1 kJ/mol total enthalpy | 0 kJ/mol | -799 kJ/mol | 0 kJ/mol | -1245 kJ/mol  | H_initial = -799 kJ/mol | | H_final = -1245 kJ/mol |  ΔH_rxn^0 | -1245 kJ/mol - -799 kJ/mol = -446.3 kJ/mol (exothermic) | | |
| zinc | iron(III) chloride | iron | zinc chloride molecular enthalpy | 0 kJ/mol | -399.5 kJ/mol | 0 kJ/mol | -415.1 kJ/mol total enthalpy | 0 kJ/mol | -799 kJ/mol | 0 kJ/mol | -1245 kJ/mol | H_initial = -799 kJ/mol | | H_final = -1245 kJ/mol | ΔH_rxn^0 | -1245 kJ/mol - -799 kJ/mol = -446.3 kJ/mol (exothermic) | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: Zn + FeCl_3 ⟶ Fe + ZnCl_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 Zn + 2 FeCl_3 ⟶ 2 Fe + 3 ZnCl_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Zn | 3 | -3 FeCl_3 | 2 | -2 Fe | 2 | 2 ZnCl_2 | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Zn | 3 | -3 | ([Zn])^(-3) FeCl_3 | 2 | -2 | ([FeCl3])^(-2) Fe | 2 | 2 | ([Fe])^2 ZnCl_2 | 3 | 3 | ([ZnCl2])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([Zn])^(-3) ([FeCl3])^(-2) ([Fe])^2 ([ZnCl2])^3 = (([Fe])^2 ([ZnCl2])^3)/(([Zn])^3 ([FeCl3])^2)
Construct the equilibrium constant, K, expression for: Zn + FeCl_3 ⟶ Fe + ZnCl_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 Zn + 2 FeCl_3 ⟶ 2 Fe + 3 ZnCl_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Zn | 3 | -3 FeCl_3 | 2 | -2 Fe | 2 | 2 ZnCl_2 | 3 | 3 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Zn | 3 | -3 | ([Zn])^(-3) FeCl_3 | 2 | -2 | ([FeCl3])^(-2) Fe | 2 | 2 | ([Fe])^2 ZnCl_2 | 3 | 3 | ([ZnCl2])^3 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Zn])^(-3) ([FeCl3])^(-2) ([Fe])^2 ([ZnCl2])^3 = (([Fe])^2 ([ZnCl2])^3)/(([Zn])^3 ([FeCl3])^2)

Rate of reaction

Construct the rate of reaction expression for: Zn + FeCl_3 ⟶ Fe + ZnCl_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 Zn + 2 FeCl_3 ⟶ 2 Fe + 3 ZnCl_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Zn | 3 | -3 FeCl_3 | 2 | -2 Fe | 2 | 2 ZnCl_2 | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Zn | 3 | -3 | -1/3 (Δ[Zn])/(Δt) FeCl_3 | 2 | -2 | -1/2 (Δ[FeCl3])/(Δt) Fe | 2 | 2 | 1/2 (Δ[Fe])/(Δt) ZnCl_2 | 3 | 3 | 1/3 (Δ[ZnCl2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/3 (Δ[Zn])/(Δt) = -1/2 (Δ[FeCl3])/(Δt) = 1/2 (Δ[Fe])/(Δt) = 1/3 (Δ[ZnCl2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: Zn + FeCl_3 ⟶ Fe + ZnCl_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 Zn + 2 FeCl_3 ⟶ 2 Fe + 3 ZnCl_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Zn | 3 | -3 FeCl_3 | 2 | -2 Fe | 2 | 2 ZnCl_2 | 3 | 3 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Zn | 3 | -3 | -1/3 (Δ[Zn])/(Δt) FeCl_3 | 2 | -2 | -1/2 (Δ[FeCl3])/(Δt) Fe | 2 | 2 | 1/2 (Δ[Fe])/(Δt) ZnCl_2 | 3 | 3 | 1/3 (Δ[ZnCl2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[Zn])/(Δt) = -1/2 (Δ[FeCl3])/(Δt) = 1/2 (Δ[Fe])/(Δt) = 1/3 (Δ[ZnCl2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | zinc | iron(III) chloride | iron | zinc chloride formula | Zn | FeCl_3 | Fe | ZnCl_2 Hill formula | Zn | Cl_3Fe | Fe | Cl_2Zn name | zinc | iron(III) chloride | iron | zinc chloride IUPAC name | zinc | trichloroiron | iron | zinc dichloride
| zinc | iron(III) chloride | iron | zinc chloride formula | Zn | FeCl_3 | Fe | ZnCl_2 Hill formula | Zn | Cl_3Fe | Fe | Cl_2Zn name | zinc | iron(III) chloride | iron | zinc chloride IUPAC name | zinc | trichloroiron | iron | zinc dichloride

Substance properties

 | zinc | iron(III) chloride | iron | zinc chloride molar mass | 65.38 g/mol | 162.2 g/mol | 55.845 g/mol | 136.3 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | solid (at STP) melting point | 420 °C | 304 °C | 1535 °C | 293 °C boiling point | 907 °C | | 2750 °C |  density | 7.14 g/cm^3 | | 7.874 g/cm^3 |  solubility in water | insoluble | | insoluble | soluble odor | odorless | | | odorless
| zinc | iron(III) chloride | iron | zinc chloride molar mass | 65.38 g/mol | 162.2 g/mol | 55.845 g/mol | 136.3 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | solid (at STP) melting point | 420 °C | 304 °C | 1535 °C | 293 °C boiling point | 907 °C | | 2750 °C | density | 7.14 g/cm^3 | | 7.874 g/cm^3 | solubility in water | insoluble | | insoluble | soluble odor | odorless | | | odorless

Units