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Cl2 + Ba(OH)2 = H2O + BaCl2 + Ba(ClO)2

Input interpretation

Cl_2 chlorine + Ba(OH)_2 barium hydroxide ⟶ H_2O water + BaCl_2 barium chloride + Ba(ClO)2
Cl_2 chlorine + Ba(OH)_2 barium hydroxide ⟶ H_2O water + BaCl_2 barium chloride + Ba(ClO)2

Balanced equation

Balance the chemical equation algebraically: Cl_2 + Ba(OH)_2 ⟶ H_2O + BaCl_2 + Ba(ClO)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cl_2 + c_2 Ba(OH)_2 ⟶ c_3 H_2O + c_4 BaCl_2 + c_5 Ba(ClO)2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, Ba, H and O: Cl: | 2 c_1 = 2 c_4 + 2 c_5 Ba: | c_2 = c_4 + c_5 H: | 2 c_2 = 2 c_3 O: | 2 c_2 = c_3 + 2 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 2 c_4 = 1 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 Cl_2 + 2 Ba(OH)_2 ⟶ 2 H_2O + BaCl_2 + Ba(ClO)2
Balance the chemical equation algebraically: Cl_2 + Ba(OH)_2 ⟶ H_2O + BaCl_2 + Ba(ClO)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Cl_2 + c_2 Ba(OH)_2 ⟶ c_3 H_2O + c_4 BaCl_2 + c_5 Ba(ClO)2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, Ba, H and O: Cl: | 2 c_1 = 2 c_4 + 2 c_5 Ba: | c_2 = c_4 + c_5 H: | 2 c_2 = 2 c_3 O: | 2 c_2 = c_3 + 2 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 2 c_3 = 2 c_4 = 1 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 Cl_2 + 2 Ba(OH)_2 ⟶ 2 H_2O + BaCl_2 + Ba(ClO)2

Structures

+ ⟶ + + Ba(ClO)2
+ ⟶ + + Ba(ClO)2

Names

chlorine + barium hydroxide ⟶ water + barium chloride + Ba(ClO)2
chlorine + barium hydroxide ⟶ water + barium chloride + Ba(ClO)2

Equilibrium constant

Construct the equilibrium constant, K, expression for: Cl_2 + Ba(OH)_2 ⟶ H_2O + BaCl_2 + Ba(ClO)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 Cl_2 + 2 Ba(OH)_2 ⟶ 2 H_2O + BaCl_2 + Ba(ClO)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 2 | -2 Ba(OH)_2 | 2 | -2 H_2O | 2 | 2 BaCl_2 | 1 | 1 Ba(ClO)2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cl_2 | 2 | -2 | ([Cl2])^(-2) Ba(OH)_2 | 2 | -2 | ([Ba(OH)2])^(-2) H_2O | 2 | 2 | ([H2O])^2 BaCl_2 | 1 | 1 | [BaCl2] Ba(ClO)2 | 1 | 1 | [Ba(ClO)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cl2])^(-2) ([Ba(OH)2])^(-2) ([H2O])^2 [BaCl2] [Ba(ClO)2] = (([H2O])^2 [BaCl2] [Ba(ClO)2])/(([Cl2])^2 ([Ba(OH)2])^2)
Construct the equilibrium constant, K, expression for: Cl_2 + Ba(OH)_2 ⟶ H_2O + BaCl_2 + Ba(ClO)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 Cl_2 + 2 Ba(OH)_2 ⟶ 2 H_2O + BaCl_2 + Ba(ClO)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 2 | -2 Ba(OH)_2 | 2 | -2 H_2O | 2 | 2 BaCl_2 | 1 | 1 Ba(ClO)2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Cl_2 | 2 | -2 | ([Cl2])^(-2) Ba(OH)_2 | 2 | -2 | ([Ba(OH)2])^(-2) H_2O | 2 | 2 | ([H2O])^2 BaCl_2 | 1 | 1 | [BaCl2] Ba(ClO)2 | 1 | 1 | [Ba(ClO)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Cl2])^(-2) ([Ba(OH)2])^(-2) ([H2O])^2 [BaCl2] [Ba(ClO)2] = (([H2O])^2 [BaCl2] [Ba(ClO)2])/(([Cl2])^2 ([Ba(OH)2])^2)

Rate of reaction

Construct the rate of reaction expression for: Cl_2 + Ba(OH)_2 ⟶ H_2O + BaCl_2 + Ba(ClO)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 Cl_2 + 2 Ba(OH)_2 ⟶ 2 H_2O + BaCl_2 + Ba(ClO)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 2 | -2 Ba(OH)_2 | 2 | -2 H_2O | 2 | 2 BaCl_2 | 1 | 1 Ba(ClO)2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cl_2 | 2 | -2 | -1/2 (Δ[Cl2])/(Δt) Ba(OH)_2 | 2 | -2 | -1/2 (Δ[Ba(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) BaCl_2 | 1 | 1 | (Δ[BaCl2])/(Δt) Ba(ClO)2 | 1 | 1 | (Δ[Ba(ClO)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[Cl2])/(Δt) = -1/2 (Δ[Ba(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[BaCl2])/(Δt) = (Δ[Ba(ClO)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: Cl_2 + Ba(OH)_2 ⟶ H_2O + BaCl_2 + Ba(ClO)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 Cl_2 + 2 Ba(OH)_2 ⟶ 2 H_2O + BaCl_2 + Ba(ClO)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Cl_2 | 2 | -2 Ba(OH)_2 | 2 | -2 H_2O | 2 | 2 BaCl_2 | 1 | 1 Ba(ClO)2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Cl_2 | 2 | -2 | -1/2 (Δ[Cl2])/(Δt) Ba(OH)_2 | 2 | -2 | -1/2 (Δ[Ba(OH)2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) BaCl_2 | 1 | 1 | (Δ[BaCl2])/(Δt) Ba(ClO)2 | 1 | 1 | (Δ[Ba(ClO)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[Cl2])/(Δt) = -1/2 (Δ[Ba(OH)2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = (Δ[BaCl2])/(Δt) = (Δ[Ba(ClO)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| chlorine | barium hydroxide | water | barium chloride | Ba(ClO)2 formula | Cl_2 | Ba(OH)_2 | H_2O | BaCl_2 | Ba(ClO)2 Hill formula | Cl_2 | BaH_2O_2 | H_2O | BaCl_2 | BaCl2O2 name | chlorine | barium hydroxide | water | barium chloride | IUPAC name | molecular chlorine | barium(+2) cation dihydroxide | water | barium(+2) cation dichloride |
| chlorine | barium hydroxide | water | barium chloride | Ba(ClO)2 formula | Cl_2 | Ba(OH)_2 | H_2O | BaCl_2 | Ba(ClO)2 Hill formula | Cl_2 | BaH_2O_2 | H_2O | BaCl_2 | BaCl2O2 name | chlorine | barium hydroxide | water | barium chloride | IUPAC name | molecular chlorine | barium(+2) cation dihydroxide | water | barium(+2) cation dichloride |

Substance properties

| chlorine | barium hydroxide | water | barium chloride | Ba(ClO)2 molar mass | 70.9 g/mol | 171.34 g/mol | 18.015 g/mol | 208.2 g/mol | 240.23 g/mol phase | gas (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) | melting point | -101 °C | 300 °C | 0 °C | 963 °C | boiling point | -34 °C | | 99.9839 °C | | density | 0.003214 g/cm^3 (at 0 °C) | 2.2 g/cm^3 | 1 g/cm^3 | 3.856 g/cm^3 | surface tension | | | 0.0728 N/m | | dynamic viscosity | | | 8.9×10^-4 Pa s (at 25 °C) | | odor | | | odorless | odorless |
| chlorine | barium hydroxide | water | barium chloride | Ba(ClO)2 molar mass | 70.9 g/mol | 171.34 g/mol | 18.015 g/mol | 208.2 g/mol | 240.23 g/mol phase | gas (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) | melting point | -101 °C | 300 °C | 0 °C | 963 °C | boiling point | -34 °C | | 99.9839 °C | | density | 0.003214 g/cm^3 (at 0 °C) | 2.2 g/cm^3 | 1 g/cm^3 | 3.856 g/cm^3 | surface tension | | | 0.0728 N/m | | dynamic viscosity | | | 8.9×10^-4 Pa s (at 25 °C) | | odor | | | odorless | odorless |

Units

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