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mass fractions of beryllium oxide

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beryllium oxide | elemental composition
beryllium oxide | elemental composition

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Find the elemental composition for beryllium oxide in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: BeO Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule:  | number of atoms  Be (beryllium) | 1  O (oxygen) | 1  N_atoms = 1 + 1 = 2 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work:  | number of atoms | atom fraction  Be (beryllium) | 1 | 1/2  O (oxygen) | 1 | 1/2 Check: 1/2 + 1/2 = 1 Compute atom percents using the atom fractions:  | number of atoms | atom percent  Be (beryllium) | 1 | 1/2 × 100% = 50.0%  O (oxygen) | 1 | 1/2 × 100% = 50.0% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | number of atoms | atom percent | atomic mass/u  Be (beryllium) | 1 | 50.0% | 9.0121831  O (oxygen) | 1 | 50.0% | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m:  | number of atoms | atom percent | atomic mass/u | mass/u  Be (beryllium) | 1 | 50.0% | 9.0121831 | 1 × 9.0121831 = 9.0121831  O (oxygen) | 1 | 50.0% | 15.999 | 1 × 15.999 = 15.999  m = 9.0121831 u + 15.999 u = 25.0111831 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work:  | number of atoms | atom percent | mass fraction  Be (beryllium) | 1 | 50.0% | 9.0121831/25.0111831  O (oxygen) | 1 | 50.0% | 15.999/25.0111831 Check: 9.0121831/25.0111831 + 15.999/25.0111831 = 1 Compute mass percents using the mass fractions: Answer: |   | | number of atoms | atom percent | mass percent  Be (beryllium) | 1 | 50.0% | 9.0121831/25.0111831 × 100% = 36.03%  O (oxygen) | 1 | 50.0% | 15.999/25.0111831 × 100% = 63.97%
Find the elemental composition for beryllium oxide in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: BeO Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms Be (beryllium) | 1 O (oxygen) | 1 N_atoms = 1 + 1 = 2 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction Be (beryllium) | 1 | 1/2 O (oxygen) | 1 | 1/2 Check: 1/2 + 1/2 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent Be (beryllium) | 1 | 1/2 × 100% = 50.0% O (oxygen) | 1 | 1/2 × 100% = 50.0% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u Be (beryllium) | 1 | 50.0% | 9.0121831 O (oxygen) | 1 | 50.0% | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u Be (beryllium) | 1 | 50.0% | 9.0121831 | 1 × 9.0121831 = 9.0121831 O (oxygen) | 1 | 50.0% | 15.999 | 1 × 15.999 = 15.999 m = 9.0121831 u + 15.999 u = 25.0111831 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction Be (beryllium) | 1 | 50.0% | 9.0121831/25.0111831 O (oxygen) | 1 | 50.0% | 15.999/25.0111831 Check: 9.0121831/25.0111831 + 15.999/25.0111831 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent Be (beryllium) | 1 | 50.0% | 9.0121831/25.0111831 × 100% = 36.03% O (oxygen) | 1 | 50.0% | 15.999/25.0111831 × 100% = 63.97%

Mass fraction pie chart

Mass fraction pie chart
Mass fraction pie chart