O2 + Al = AlO

oxygen + aluminum ⟶ AlO

Balance the chemical equation algebraically: + ⟶ AlO Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 AlO Set the number of atoms in the reactants equal to the number of atoms in the products for O and Al: O: | 2 c_1 = c_3 Al: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 2 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | + 2 ⟶ 2 AlO

+ ⟶ AlO

oxygen + aluminum ⟶ AlO

| oxygen | aluminum | AlO formula | | | AlO Hill formula | O_2 | Al | AlO name | oxygen | aluminum | IUPAC name | molecular oxygen | aluminum |

| oxygen | aluminum | AlO molar mass | 31.998 g/mol | 26.9815385 g/mol | 42.981 g/mol phase | gas (at STP) | solid (at STP) | melting point | -218 °C | 660.4 °C | boiling point | -183 °C | 2460 °C | density | 0.001429 g/cm^3 (at 0 °C) | 2.7 g/cm^3 | solubility in water | | insoluble | surface tension | 0.01347 N/m | 0.817 N/m | dynamic viscosity | 2.055×10^-5 Pa s (at 25 °C) | 1.5×10^-4 Pa s (at 760 °C) | odor | odorless | odorless |