Input interpretation
![tetrasodium ethylenediaminetetraacetate | molar mass](../image_source/4b6c50063ab0842a6fb67ab5355c23b4.png)
tetrasodium ethylenediaminetetraacetate | molar mass
Result
![Find the molar mass, M, for tetrasodium ethylenediaminetetraacetate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (NaOCOCH_2)_4N_2(CH_2)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 10 H (hydrogen) | 12 N (nitrogen) | 2 Na (sodium) | 4 O (oxygen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 10 | 12.011 H (hydrogen) | 12 | 1.008 N (nitrogen) | 2 | 14.007 Na (sodium) | 4 | 22.98976928 O (oxygen) | 8 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 Na (sodium) | 4 | 22.98976928 | 4 × 22.98976928 = 91.95907712 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 M = 120.110 g/mol + 12.096 g/mol + 28.014 g/mol + 91.95907712 g/mol + 127.992 g/mol = 380.171 g/mol](../image_source/aa0bccd7e37736dc853c9978a0f74f4b.png)
Find the molar mass, M, for tetrasodium ethylenediaminetetraacetate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (NaOCOCH_2)_4N_2(CH_2)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 10 H (hydrogen) | 12 N (nitrogen) | 2 Na (sodium) | 4 O (oxygen) | 8 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 10 | 12.011 H (hydrogen) | 12 | 1.008 N (nitrogen) | 2 | 14.007 Na (sodium) | 4 | 22.98976928 O (oxygen) | 8 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 Na (sodium) | 4 | 22.98976928 | 4 × 22.98976928 = 91.95907712 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 M = 120.110 g/mol + 12.096 g/mol + 28.014 g/mol + 91.95907712 g/mol + 127.992 g/mol = 380.171 g/mol
Unit conversion
![0.38017 kg/mol (kilograms per mole)](../image_source/e0f3f6e8012e9e0944341588c8b1b789.png)
0.38017 kg/mol (kilograms per mole)
Comparisons
![≈ 0.53 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/72f2960db9f62fb50b62297e926a558e.png)
≈ 0.53 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/af3153ebc6324a70d3607ca7fa21cc58.png)
≈ 2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 6.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/be84c9623b48f35e2244d0681ae5c95f.png)
≈ 6.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 6.3×10^-22 grams | 6.3×10^-25 kg (kilograms) | 380 u (unified atomic mass units) | 380 Da (daltons)](../image_source/a4dcf9b049e2da6c23b0daf0b7b2351e.png)
Mass of a molecule m from m = M/N_A: | 6.3×10^-22 grams | 6.3×10^-25 kg (kilograms) | 380 u (unified atomic mass units) | 380 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 380](../image_source/e2208b899542dfe06c167e43615a7339.png)
Relative molecular mass M_r from M_r = M_u/M: | 380