Input interpretation
![2-bromo-5-fluorophenol | molar mass](../image_source/65ee3b0f5735997b6719e8aa57940f4c.png)
2-bromo-5-fluorophenol | molar mass
Result
![Find the molar mass, M, for 2-bromo-5-fluorophenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BrC_6H_3(F)OH Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 6 F (fluorine) | 1 H (hydrogen) | 4 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 6 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 4 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 79.904 g/mol + 72.066 g/mol + 18.998403163 g/mol + 4.032 g/mol + 15.999 g/mol = 190.999 g/mol](../image_source/1c6bc7b8bb43630bd84ca513b07f7b62.png)
Find the molar mass, M, for 2-bromo-5-fluorophenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BrC_6H_3(F)OH Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 6 F (fluorine) | 1 H (hydrogen) | 4 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 6 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 4 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 79.904 g/mol + 72.066 g/mol + 18.998403163 g/mol + 4.032 g/mol + 15.999 g/mol = 190.999 g/mol
Unit conversion
![0.191 kg/mol (kilograms per mole)](../image_source/7170ebcc04c2bff2baf923e518e124e1.png)
0.191 kg/mol (kilograms per mole)
Comparisons
![≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/0a55836767b0c74b90ea67f9ebf6139c.png)
≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.98 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/272b24c8036807f0855cd92c6b600b8a.png)
≈ 0.98 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/bc9005162455fe91261cee964d4b624e.png)
≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 191 u (unified atomic mass units) | 191 Da (daltons)](../image_source/f529f9a577a5e85bdc11877882d92ace.png)
Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 191 u (unified atomic mass units) | 191 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 191](../image_source/c7e5c64cb77d635e6c483f0a8a718f78.png)
Relative molecular mass M_r from M_r = M_u/M: | 191