Input interpretation
Na_2S sodium sulfide + PbBr_2 lead(II) bromide ⟶ NaBr sodium bromide + PbS lead sulfide
Balanced equation
Balance the chemical equation algebraically: Na_2S + PbBr_2 ⟶ NaBr + PbS Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Na_2S + c_2 PbBr_2 ⟶ c_3 NaBr + c_4 PbS Set the number of atoms in the reactants equal to the number of atoms in the products for Na, S, Br and Pb: Na: | 2 c_1 = c_3 S: | c_1 = c_4 Br: | 2 c_2 = c_3 Pb: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | Na_2S + PbBr_2 ⟶ 2 NaBr + PbS
Structures
+ ⟶ +
Names
sodium sulfide + lead(II) bromide ⟶ sodium bromide + lead sulfide
Reaction thermodynamics
Enthalpy
| sodium sulfide | lead(II) bromide | sodium bromide | lead sulfide molecular enthalpy | -364.8 kJ/mol | -278.7 kJ/mol | -361.1 kJ/mol | -100.4 kJ/mol total enthalpy | -364.8 kJ/mol | -278.7 kJ/mol | -722.2 kJ/mol | -100.4 kJ/mol | H_initial = -643.5 kJ/mol | | H_final = -822.6 kJ/mol | ΔH_rxn^0 | -822.6 kJ/mol - -643.5 kJ/mol = -179.1 kJ/mol (exothermic) | | |
Gibbs free energy
| sodium sulfide | lead(II) bromide | sodium bromide | lead sulfide molecular free energy | -349.8 kJ/mol | -261.9 kJ/mol | -349 kJ/mol | -98.7 kJ/mol total free energy | -349.8 kJ/mol | -261.9 kJ/mol | -698 kJ/mol | -98.7 kJ/mol | G_initial = -611.7 kJ/mol | | G_final = -796.7 kJ/mol | ΔG_rxn^0 | -796.7 kJ/mol - -611.7 kJ/mol = -185 kJ/mol (exergonic) | | |
Equilibrium constant
Construct the equilibrium constant, K, expression for: Na_2S + PbBr_2 ⟶ NaBr + PbS Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: Na_2S + PbBr_2 ⟶ 2 NaBr + PbS Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Na_2S | 1 | -1 PbBr_2 | 1 | -1 NaBr | 2 | 2 PbS | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Na_2S | 1 | -1 | ([Na2S])^(-1) PbBr_2 | 1 | -1 | ([PbBr2])^(-1) NaBr | 2 | 2 | ([NaBr])^2 PbS | 1 | 1 | [PbS] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Na2S])^(-1) ([PbBr2])^(-1) ([NaBr])^2 [PbS] = (([NaBr])^2 [PbS])/([Na2S] [PbBr2])
Rate of reaction
Construct the rate of reaction expression for: Na_2S + PbBr_2 ⟶ NaBr + PbS Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: Na_2S + PbBr_2 ⟶ 2 NaBr + PbS Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Na_2S | 1 | -1 PbBr_2 | 1 | -1 NaBr | 2 | 2 PbS | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Na_2S | 1 | -1 | -(Δ[Na2S])/(Δt) PbBr_2 | 1 | -1 | -(Δ[PbBr2])/(Δt) NaBr | 2 | 2 | 1/2 (Δ[NaBr])/(Δt) PbS | 1 | 1 | (Δ[PbS])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[Na2S])/(Δt) = -(Δ[PbBr2])/(Δt) = 1/2 (Δ[NaBr])/(Δt) = (Δ[PbS])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
| sodium sulfide | lead(II) bromide | sodium bromide | lead sulfide formula | Na_2S | PbBr_2 | NaBr | PbS Hill formula | Na_2S_1 | Br_2Pb | BrNa | PbS name | sodium sulfide | lead(II) bromide | sodium bromide | lead sulfide
Substance properties
| sodium sulfide | lead(II) bromide | sodium bromide | lead sulfide molar mass | 78.04 g/mol | 367 g/mol | 102.89 g/mol | 239.3 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | solid (at STP) melting point | 1172 °C | 371 °C | 755 °C | 1114 °C boiling point | | 892 °C | 1396 °C | 1344 °C density | 1.856 g/cm^3 | 6.66 g/cm^3 | 3.2 g/cm^3 | 7.5 g/cm^3 solubility in water | | | soluble | insoluble dynamic viscosity | | 0.0088 Pa s (at 382 °C) | |
Units