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molar mass of undecanoyl chloride

Input interpretation

undecanoyl chloride | molar mass
undecanoyl chloride | molar mass

Result

Find the molar mass, M, for undecanoyl chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3(CH_2)_9COCl Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 11  Cl (chlorine) | 1  H (hydrogen) | 21  O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 11 | 12.011  Cl (chlorine) | 1 | 35.45  H (hydrogen) | 21 | 1.008  O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121  Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45  H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168  O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999  M = 132.121 g/mol + 35.45 g/mol + 21.168 g/mol + 15.999 g/mol = 204.74 g/mol
Find the molar mass, M, for undecanoyl chloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CH_3(CH_2)_9COCl Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 11 Cl (chlorine) | 1 H (hydrogen) | 21 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 11 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 21 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 132.121 g/mol + 35.45 g/mol + 21.168 g/mol + 15.999 g/mol = 204.74 g/mol

Unit conversion

0.2047 kg/mol (kilograms per mole)
0.2047 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.28 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.28 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3.5 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 3.4×10^-22 grams  | 3.4×10^-25 kg (kilograms)  | 205 u (unified atomic mass units)  | 205 Da (daltons)
Mass of a molecule m from m = M/N_A: | 3.4×10^-22 grams | 3.4×10^-25 kg (kilograms) | 205 u (unified atomic mass units) | 205 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 205
Relative molecular mass M_r from M_r = M_u/M: | 205