Zn + BCl3 = ZnCl2 + B

zinc + boron trichloride ⟶ zinc chloride + boron

Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for Zn, B and Cl: Zn: | c_1 = c_3 B: | c_2 = c_4 Cl: | 3 c_2 = 2 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 1 c_3 = 3/2 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 2 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 + 2 ⟶ 3 + 2

+ ⟶ +

zinc + boron trichloride ⟶ zinc chloride + boron

| zinc | boron trichloride | zinc chloride | boron molecular enthalpy | 0 kJ/mol | -403.8 kJ/mol | -415.1 kJ/mol | 0 kJ/mol total enthalpy | 0 kJ/mol | -807.6 kJ/mol | -1245 kJ/mol | 0 kJ/mol | H_initial = -807.6 kJ/mol | | H_final = -1245 kJ/mol | ΔH_rxn^0 | -1245 kJ/mol - -807.6 kJ/mol = -437.7 kJ/mol (exothermic) | | |

| zinc | boron trichloride | zinc chloride | boron Hill formula | Zn | BCl_3 | Cl_2Zn | B name | zinc | boron trichloride | zinc chloride | boron IUPAC name | zinc | trichloroborane | zinc dichloride | boron

| zinc | boron trichloride | zinc chloride | boron molar mass | 65.38 g/mol | 117.2 g/mol | 136.3 g/mol | 10.81 g/mol phase | solid (at STP) | gas (at STP) | solid (at STP) | solid (at STP) melting point | 420 °C | -107 °C | 293 °C | 2075 °C boiling point | 907 °C | 12.4 °C | | 4000 °C density | 7.14 g/cm^3 | 0.004789 g/cm^3 (at 25 °C) | | 2.34 g/cm^3 solubility in water | insoluble | decomposes | soluble | insoluble surface tension | | 0.0167 N/m | | dynamic viscosity | | 0.00104 Pa s (at 10 °C) | | odor | odorless | | odorless |