Input interpretation
aluminum nitride | molar mass
Result
Find the molar mass, M, for aluminum nitride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: AlN Use the chemical formula to count the number of atoms, N_i, for each element: | number of atoms Al (aluminum) | 1 N (nitrogen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | number of atoms | atomic mass/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 N (nitrogen) | 1 | 14.007 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | number of atoms | atomic mass/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 1 | 26.9815385 | 1 × 26.9815385 = 26.9815385 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 M = 26.9815385 g/mol + 14.007 g/mol = 40.989 g/mol
Unit conversion
0.040989 kg/mol (kilograms per mole)
Comparisons
≈ ( 0.057 ≈ 1/18 ) × molar mass of fullerene (≈ 721 g/mol )
≈ ( 0.21 ≈ 1/5 ) × molar mass of caffeine (≈ 194 g/mol )
≈ 0.7 × molar mass of sodium chloride (≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 6.8×10^-23 grams | 6.8×10^-26 kg (kilograms) | 41 u (unified atomic mass units) | 41 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 41