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O2 + C6H5C2H5 = H2O + CO2 + C6H5OH

Input interpretation

O_2 oxygen + C_6H_5C_2H_5 ethylbenzene ⟶ H_2O water + CO_2 carbon dioxide + C_6H_5OH phenol
O_2 oxygen + C_6H_5C_2H_5 ethylbenzene ⟶ H_2O water + CO_2 carbon dioxide + C_6H_5OH phenol

Balanced equation

Balance the chemical equation algebraically: O_2 + C_6H_5C_2H_5 ⟶ H_2O + CO_2 + C_6H_5OH Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 C_6H_5C_2H_5 ⟶ c_3 H_2O + c_4 CO_2 + c_5 C_6H_5OH Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 = c_3 + 2 c_4 + c_5 C: | 8 c_2 = c_4 + 6 c_5 H: | 10 c_2 = 2 c_3 + 6 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_2 = 1 c_3 = (3 c_1)/7 + 1/2 c_4 = (6 c_1)/7 - 1 c_5 = 3/2 - c_1/7 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_2 = 2 c_3 = (3 c_1)/7 + 1 c_4 = (6 c_1)/7 - 2 c_5 = 3 - c_1/7 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 7 and solve for the remaining coefficients: c_1 = 7 c_2 = 2 c_3 = 4 c_4 = 4 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 7 O_2 + 2 C_6H_5C_2H_5 ⟶ 4 H_2O + 4 CO_2 + 2 C_6H_5OH
Balance the chemical equation algebraically: O_2 + C_6H_5C_2H_5 ⟶ H_2O + CO_2 + C_6H_5OH Add stoichiometric coefficients, c_i, to the reactants and products: c_1 O_2 + c_2 C_6H_5C_2H_5 ⟶ c_3 H_2O + c_4 CO_2 + c_5 C_6H_5OH Set the number of atoms in the reactants equal to the number of atoms in the products for O, C and H: O: | 2 c_1 = c_3 + 2 c_4 + c_5 C: | 8 c_2 = c_4 + 6 c_5 H: | 10 c_2 = 2 c_3 + 6 c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_2 = 1 c_3 = (3 c_1)/7 + 1/2 c_4 = (6 c_1)/7 - 1 c_5 = 3/2 - c_1/7 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_2 = 2 c_3 = (3 c_1)/7 + 1 c_4 = (6 c_1)/7 - 2 c_5 = 3 - c_1/7 The resulting system of equations is still underdetermined, so an additional coefficient must be set arbitrarily. Set c_1 = 7 and solve for the remaining coefficients: c_1 = 7 c_2 = 2 c_3 = 4 c_4 = 4 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 7 O_2 + 2 C_6H_5C_2H_5 ⟶ 4 H_2O + 4 CO_2 + 2 C_6H_5OH

Structures

 + ⟶ + +
+ ⟶ + +

Names

oxygen + ethylbenzene ⟶ water + carbon dioxide + phenol
oxygen + ethylbenzene ⟶ water + carbon dioxide + phenol

Equilibrium constant

Construct the equilibrium constant, K, expression for: O_2 + C_6H_5C_2H_5 ⟶ H_2O + CO_2 + C_6H_5OH Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 7 O_2 + 2 C_6H_5C_2H_5 ⟶ 4 H_2O + 4 CO_2 + 2 C_6H_5OH Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 7 | -7 C_6H_5C_2H_5 | 2 | -2 H_2O | 4 | 4 CO_2 | 4 | 4 C_6H_5OH | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression O_2 | 7 | -7 | ([O2])^(-7) C_6H_5C_2H_5 | 2 | -2 | ([C6H5C2H5])^(-2) H_2O | 4 | 4 | ([H2O])^4 CO_2 | 4 | 4 | ([CO2])^4 C_6H_5OH | 2 | 2 | ([C6H5OH])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([O2])^(-7) ([C6H5C2H5])^(-2) ([H2O])^4 ([CO2])^4 ([C6H5OH])^2 = (([H2O])^4 ([CO2])^4 ([C6H5OH])^2)/(([O2])^7 ([C6H5C2H5])^2)
Construct the equilibrium constant, K, expression for: O_2 + C_6H_5C_2H_5 ⟶ H_2O + CO_2 + C_6H_5OH Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 7 O_2 + 2 C_6H_5C_2H_5 ⟶ 4 H_2O + 4 CO_2 + 2 C_6H_5OH Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 7 | -7 C_6H_5C_2H_5 | 2 | -2 H_2O | 4 | 4 CO_2 | 4 | 4 C_6H_5OH | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression O_2 | 7 | -7 | ([O2])^(-7) C_6H_5C_2H_5 | 2 | -2 | ([C6H5C2H5])^(-2) H_2O | 4 | 4 | ([H2O])^4 CO_2 | 4 | 4 | ([CO2])^4 C_6H_5OH | 2 | 2 | ([C6H5OH])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([O2])^(-7) ([C6H5C2H5])^(-2) ([H2O])^4 ([CO2])^4 ([C6H5OH])^2 = (([H2O])^4 ([CO2])^4 ([C6H5OH])^2)/(([O2])^7 ([C6H5C2H5])^2)

Rate of reaction

Construct the rate of reaction expression for: O_2 + C_6H_5C_2H_5 ⟶ H_2O + CO_2 + C_6H_5OH Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 7 O_2 + 2 C_6H_5C_2H_5 ⟶ 4 H_2O + 4 CO_2 + 2 C_6H_5OH Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 7 | -7 C_6H_5C_2H_5 | 2 | -2 H_2O | 4 | 4 CO_2 | 4 | 4 C_6H_5OH | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term O_2 | 7 | -7 | -1/7 (Δ[O2])/(Δt) C_6H_5C_2H_5 | 2 | -2 | -1/2 (Δ[C6H5C2H5])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) CO_2 | 4 | 4 | 1/4 (Δ[CO2])/(Δt) C_6H_5OH | 2 | 2 | 1/2 (Δ[C6H5OH])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/7 (Δ[O2])/(Δt) = -1/2 (Δ[C6H5C2H5])/(Δt) = 1/4 (Δ[H2O])/(Δt) = 1/4 (Δ[CO2])/(Δt) = 1/2 (Δ[C6H5OH])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: O_2 + C_6H_5C_2H_5 ⟶ H_2O + CO_2 + C_6H_5OH Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 7 O_2 + 2 C_6H_5C_2H_5 ⟶ 4 H_2O + 4 CO_2 + 2 C_6H_5OH Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i O_2 | 7 | -7 C_6H_5C_2H_5 | 2 | -2 H_2O | 4 | 4 CO_2 | 4 | 4 C_6H_5OH | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term O_2 | 7 | -7 | -1/7 (Δ[O2])/(Δt) C_6H_5C_2H_5 | 2 | -2 | -1/2 (Δ[C6H5C2H5])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) CO_2 | 4 | 4 | 1/4 (Δ[CO2])/(Δt) C_6H_5OH | 2 | 2 | 1/2 (Δ[C6H5OH])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/7 (Δ[O2])/(Δt) = -1/2 (Δ[C6H5C2H5])/(Δt) = 1/4 (Δ[H2O])/(Δt) = 1/4 (Δ[CO2])/(Δt) = 1/2 (Δ[C6H5OH])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | oxygen | ethylbenzene | water | carbon dioxide | phenol formula | O_2 | C_6H_5C_2H_5 | H_2O | CO_2 | C_6H_5OH Hill formula | O_2 | C_8H_10 | H_2O | CO_2 | C_6H_6O name | oxygen | ethylbenzene | water | carbon dioxide | phenol IUPAC name | molecular oxygen | ethylbenzene | water | carbon dioxide | phenol
| oxygen | ethylbenzene | water | carbon dioxide | phenol formula | O_2 | C_6H_5C_2H_5 | H_2O | CO_2 | C_6H_5OH Hill formula | O_2 | C_8H_10 | H_2O | CO_2 | C_6H_6O name | oxygen | ethylbenzene | water | carbon dioxide | phenol IUPAC name | molecular oxygen | ethylbenzene | water | carbon dioxide | phenol