Input interpretation
![barium calcium titanate | molar mass](../image_source/5c363681753d19fd63c920e8a14d1bdc.png)
barium calcium titanate | molar mass
Result
![Find the molar mass, M, for barium calcium titanate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (Ba, Ca)TiO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ba (barium) | 1 Ca (calcium) | 1 O (oxygen) | 1 Ti (titanium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ba (barium) | 1 | 137.327 Ca (calcium) | 1 | 40.078 O (oxygen) | 1 | 15.999 Ti (titanium) | 1 | 47.867 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ba (barium) | 1 | 137.327 | 1 × 137.327 = 137.327 Ca (calcium) | 1 | 40.078 | 1 × 40.078 = 40.078 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 Ti (titanium) | 1 | 47.867 | 1 × 47.867 = 47.867 M = 137.327 g/mol + 40.078 g/mol + 15.999 g/mol + 47.867 g/mol = 241.271 g/mol](../image_source/7831f60aaca6acfe29a3e543cd325818.png)
Find the molar mass, M, for barium calcium titanate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (Ba, Ca)TiO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Ba (barium) | 1 Ca (calcium) | 1 O (oxygen) | 1 Ti (titanium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Ba (barium) | 1 | 137.327 Ca (calcium) | 1 | 40.078 O (oxygen) | 1 | 15.999 Ti (titanium) | 1 | 47.867 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Ba (barium) | 1 | 137.327 | 1 × 137.327 = 137.327 Ca (calcium) | 1 | 40.078 | 1 × 40.078 = 40.078 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 Ti (titanium) | 1 | 47.867 | 1 × 47.867 = 47.867 M = 137.327 g/mol + 40.078 g/mol + 15.999 g/mol + 47.867 g/mol = 241.271 g/mol
Unit conversion
![0.24127 kg/mol (kilograms per mole)](../image_source/64e8b104197688daf8f9982fe606c239.png)
0.24127 kg/mol (kilograms per mole)
Comparisons
![≈ 0.33 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/320e08ccf6339677107289acc1ca2bc4.png)
≈ 0.33 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/d9dcbd1d1e086f8d237b32863bbd2d11.png)
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/8d6a416e89475aac46e3d4120e15803a.png)
≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 241 u (unified atomic mass units) | 241 Da (daltons)](../image_source/8f41897fb5d0dc7c2b285819e850286c.png)
Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 241 u (unified atomic mass units) | 241 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 241](../image_source/b84f7c1bed8ec8b91677ec840bde900e.png)
Relative molecular mass M_r from M_r = M_u/M: | 241