Input interpretation
![K_2SO_4 potassium sulfate + Ba(NO_3)_2 barium nitrate ⟶ KNO_3 potassium nitrate + BaSO_4 barium sulfate](../image_source/e82b4b820c3685fbf95e3a5cfe3a848c.png)
K_2SO_4 potassium sulfate + Ba(NO_3)_2 barium nitrate ⟶ KNO_3 potassium nitrate + BaSO_4 barium sulfate
Balanced equation
![Balance the chemical equation algebraically: K_2SO_4 + Ba(NO_3)_2 ⟶ KNO_3 + BaSO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 K_2SO_4 + c_2 Ba(NO_3)_2 ⟶ c_3 KNO_3 + c_4 BaSO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for K, O, S, Ba and N: K: | 2 c_1 = c_3 O: | 4 c_1 + 6 c_2 = 3 c_3 + 4 c_4 S: | c_1 = c_4 Ba: | c_2 = c_4 N: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | K_2SO_4 + Ba(NO_3)_2 ⟶ 2 KNO_3 + BaSO_4](../image_source/dd01979991c4a005875de11187958c0b.png)
Balance the chemical equation algebraically: K_2SO_4 + Ba(NO_3)_2 ⟶ KNO_3 + BaSO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 K_2SO_4 + c_2 Ba(NO_3)_2 ⟶ c_3 KNO_3 + c_4 BaSO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for K, O, S, Ba and N: K: | 2 c_1 = c_3 O: | 4 c_1 + 6 c_2 = 3 c_3 + 4 c_4 S: | c_1 = c_4 Ba: | c_2 = c_4 N: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | K_2SO_4 + Ba(NO_3)_2 ⟶ 2 KNO_3 + BaSO_4
Structures
![+ ⟶ +](../image_source/5e6d8be08dced1e7df030125ddba9c69.png)
+ ⟶ +
Names
![potassium sulfate + barium nitrate ⟶ potassium nitrate + barium sulfate](../image_source/9bdc602c80c5607ce0ffdec2688aa631.png)
potassium sulfate + barium nitrate ⟶ potassium nitrate + barium sulfate
Equilibrium constant
![Construct the equilibrium constant, K, expression for: K_2SO_4 + Ba(NO_3)_2 ⟶ KNO_3 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: K_2SO_4 + Ba(NO_3)_2 ⟶ 2 KNO_3 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2SO_4 | 1 | -1 Ba(NO_3)_2 | 1 | -1 KNO_3 | 2 | 2 BaSO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression K_2SO_4 | 1 | -1 | ([K2SO4])^(-1) Ba(NO_3)_2 | 1 | -1 | ([Ba(NO3)2])^(-1) KNO_3 | 2 | 2 | ([KNO3])^2 BaSO_4 | 1 | 1 | [BaSO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([K2SO4])^(-1) ([Ba(NO3)2])^(-1) ([KNO3])^2 [BaSO4] = (([KNO3])^2 [BaSO4])/([K2SO4] [Ba(NO3)2])](../image_source/3dc942dfa0df3a4844ab1c3d291431ad.png)
Construct the equilibrium constant, K, expression for: K_2SO_4 + Ba(NO_3)_2 ⟶ KNO_3 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: K_2SO_4 + Ba(NO_3)_2 ⟶ 2 KNO_3 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2SO_4 | 1 | -1 Ba(NO_3)_2 | 1 | -1 KNO_3 | 2 | 2 BaSO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression K_2SO_4 | 1 | -1 | ([K2SO4])^(-1) Ba(NO_3)_2 | 1 | -1 | ([Ba(NO3)2])^(-1) KNO_3 | 2 | 2 | ([KNO3])^2 BaSO_4 | 1 | 1 | [BaSO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([K2SO4])^(-1) ([Ba(NO3)2])^(-1) ([KNO3])^2 [BaSO4] = (([KNO3])^2 [BaSO4])/([K2SO4] [Ba(NO3)2])
Rate of reaction
![Construct the rate of reaction expression for: K_2SO_4 + Ba(NO_3)_2 ⟶ KNO_3 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: K_2SO_4 + Ba(NO_3)_2 ⟶ 2 KNO_3 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2SO_4 | 1 | -1 Ba(NO_3)_2 | 1 | -1 KNO_3 | 2 | 2 BaSO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term K_2SO_4 | 1 | -1 | -(Δ[K2SO4])/(Δt) Ba(NO_3)_2 | 1 | -1 | -(Δ[Ba(NO3)2])/(Δt) KNO_3 | 2 | 2 | 1/2 (Δ[KNO3])/(Δt) BaSO_4 | 1 | 1 | (Δ[BaSO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[K2SO4])/(Δt) = -(Δ[Ba(NO3)2])/(Δt) = 1/2 (Δ[KNO3])/(Δt) = (Δ[BaSO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/1535b365dc973b25a606abac87c193fc.png)
Construct the rate of reaction expression for: K_2SO_4 + Ba(NO_3)_2 ⟶ KNO_3 + BaSO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: K_2SO_4 + Ba(NO_3)_2 ⟶ 2 KNO_3 + BaSO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i K_2SO_4 | 1 | -1 Ba(NO_3)_2 | 1 | -1 KNO_3 | 2 | 2 BaSO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term K_2SO_4 | 1 | -1 | -(Δ[K2SO4])/(Δt) Ba(NO_3)_2 | 1 | -1 | -(Δ[Ba(NO3)2])/(Δt) KNO_3 | 2 | 2 | 1/2 (Δ[KNO3])/(Δt) BaSO_4 | 1 | 1 | (Δ[BaSO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[K2SO4])/(Δt) = -(Δ[Ba(NO3)2])/(Δt) = 1/2 (Δ[KNO3])/(Δt) = (Δ[BaSO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| potassium sulfate | barium nitrate | potassium nitrate | barium sulfate formula | K_2SO_4 | Ba(NO_3)_2 | KNO_3 | BaSO_4 Hill formula | K_2O_4S | BaN_2O_6 | KNO_3 | BaO_4S name | potassium sulfate | barium nitrate | potassium nitrate | barium sulfate IUPAC name | dipotassium sulfate | barium(+2) cation dinitrate | potassium nitrate | barium(+2) cation sulfate](../image_source/add2cb6b673dbf89c356fa7b46522b97.png)
| potassium sulfate | barium nitrate | potassium nitrate | barium sulfate formula | K_2SO_4 | Ba(NO_3)_2 | KNO_3 | BaSO_4 Hill formula | K_2O_4S | BaN_2O_6 | KNO_3 | BaO_4S name | potassium sulfate | barium nitrate | potassium nitrate | barium sulfate IUPAC name | dipotassium sulfate | barium(+2) cation dinitrate | potassium nitrate | barium(+2) cation sulfate
Substance properties
![| potassium sulfate | barium nitrate | potassium nitrate | barium sulfate molar mass | 174.25 g/mol | 261.34 g/mol | 101.1 g/mol | 233.38 g/mol phase | | solid (at STP) | solid (at STP) | solid (at STP) melting point | | 592 °C | 334 °C | 1345 °C density | | 3.23 g/cm^3 | | 4.5 g/cm^3 solubility in water | soluble | | soluble | insoluble odor | | | odorless |](../image_source/4260dc6b5fca7b7212b9e3dfb3e051cc.png)
| potassium sulfate | barium nitrate | potassium nitrate | barium sulfate molar mass | 174.25 g/mol | 261.34 g/mol | 101.1 g/mol | 233.38 g/mol phase | | solid (at STP) | solid (at STP) | solid (at STP) melting point | | 592 °C | 334 °C | 1345 °C density | | 3.23 g/cm^3 | | 4.5 g/cm^3 solubility in water | soluble | | soluble | insoluble odor | | | odorless |
Units