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molar mass of methyleugenol

Input interpretation

methyleugenol | molar mass
methyleugenol | molar mass

Result

Find the molar mass, M, for methyleugenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=CHCH_2C_6H_3(OCH_3)_2 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 11  H (hydrogen) | 14  O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 11 | 12.011  H (hydrogen) | 14 | 1.008  O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121  H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  M = 132.121 g/mol + 14.112 g/mol + 31.998 g/mol = 178.231 g/mol
Find the molar mass, M, for methyleugenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: H_2C=CHCH_2C_6H_3(OCH_3)_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 11 H (hydrogen) | 14 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 11 | 12.011 H (hydrogen) | 14 | 1.008 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 11 | 12.011 | 11 × 12.011 = 132.121 H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 132.121 g/mol + 14.112 g/mol + 31.998 g/mol = 178.231 g/mol

Unit conversion

0.17823 kg/mol (kilograms per mole)
0.17823 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.25 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.25 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.92 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.92 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 3 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 3 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 3×10^-22 grams  | 3×10^-25 kg (kilograms)  | 178 u (unified atomic mass units)  | 178 Da (daltons)
Mass of a molecule m from m = M/N_A: | 3×10^-22 grams | 3×10^-25 kg (kilograms) | 178 u (unified atomic mass units) | 178 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 178
Relative molecular mass M_r from M_r = M_u/M: | 178