Input interpretation
![chromium(III) perchlorate hexahydrate | molar mass](../image_source/aed4b4362b1d9b79968ccecc803b9a17.png)
chromium(III) perchlorate hexahydrate | molar mass
Result
![Find the molar mass, M, for chromium(III) perchlorate hexahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Cr(ClO_4)_3·6H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 1 Cr (chromium) | 1 H (hydrogen) | 3 O (oxygen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 1 | 35.45 Cr (chromium) | 1 | 51.9961 H (hydrogen) | 3 | 1.008 O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 M = 35.45 g/mol + 51.9961 g/mol + 3.024 g/mol + 79.995 g/mol = 170.47 g/mol](../image_source/c15c3ebfab60737eac5c0ab25c26fa0c.png)
Find the molar mass, M, for chromium(III) perchlorate hexahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Cr(ClO_4)_3·6H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 1 Cr (chromium) | 1 H (hydrogen) | 3 O (oxygen) | 5 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 1 | 35.45 Cr (chromium) | 1 | 51.9961 H (hydrogen) | 3 | 1.008 O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 Cr (chromium) | 1 | 51.9961 | 1 × 51.9961 = 51.9961 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 M = 35.45 g/mol + 51.9961 g/mol + 3.024 g/mol + 79.995 g/mol = 170.47 g/mol
Unit conversion
![0.17047 kg/mol (kilograms per mole)](../image_source/9e45db1a633e959b4b06a78b55af7ea3.png)
0.17047 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/a774e20c3b9163a840577b0a5d3eb39d.png)
≈ ( 0.24 ≈ 1/4 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.88 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/55ee20079cc1eca770ef9356c6a200ba.png)
≈ 0.88 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/e274f0b032718f71ac94ceb2d6b4fb96.png)
≈ 2.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.8×10^-22 grams | 2.8×10^-25 kg (kilograms) | 170 u (unified atomic mass units) | 170 Da (daltons)](../image_source/273c5b45ce45611b1c83cdf83add2b6f.png)
Mass of a molecule m from m = M/N_A: | 2.8×10^-22 grams | 2.8×10^-25 kg (kilograms) | 170 u (unified atomic mass units) | 170 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 170](../image_source/a1c34d2b35ccc6f6e01485a75c38745d.png)
Relative molecular mass M_r from M_r = M_u/M: | 170