Input interpretation
![rubidium nitrate | molar mass](../image_source/a4509ee3ee7a72d25271b02da2956e2e.png)
rubidium nitrate | molar mass
Result
![Find the molar mass, M, for rubidium nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: RbNO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i N (nitrogen) | 1 O (oxygen) | 3 Rb (rubidium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Rb (rubidium) | 1 | 85.4678 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Rb (rubidium) | 1 | 85.4678 | 1 × 85.4678 = 85.4678 M = 14.007 g/mol + 47.997 g/mol + 85.4678 g/mol = 147.472 g/mol](../image_source/cb9ade98db02e6682b9379fc4ebe637f.png)
Find the molar mass, M, for rubidium nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: RbNO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i N (nitrogen) | 1 O (oxygen) | 3 Rb (rubidium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Rb (rubidium) | 1 | 85.4678 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Rb (rubidium) | 1 | 85.4678 | 1 × 85.4678 = 85.4678 M = 14.007 g/mol + 47.997 g/mol + 85.4678 g/mol = 147.472 g/mol
Unit conversion
![0.14747 kg/mol (kilograms per mole)](../image_source/618dfd62f51400d17fdec8921c37e26a.png)
0.14747 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/02f1a8b16099c12d774f6c639f60108d.png)
≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.76 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/5b064befedc64b52834978bfe3c1b955.png)
≈ 0.76 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/79a7ac455fd87fb586049ec4671f0974.png)
≈ 2.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms) | 147 u (unified atomic mass units) | 147 Da (daltons)](../image_source/15bc5a9c21d2ec0ffdcbba62a600123d.png)
Mass of a molecule m from m = M/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms) | 147 u (unified atomic mass units) | 147 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 147](../image_source/d5fa591d53845611a453133f627f4b36.png)
Relative molecular mass M_r from M_r = M_u/M: | 147