Input interpretation
![zirconyl chloride hydrate | molar mass](../image_source/52b05d3d4d1fdc035a2bd0d330ffcb20.png)
zirconyl chloride hydrate | molar mass
Result
![Find the molar mass, M, for zirconyl chloride hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ZrOCl_2·xH_2O Use the chemical formula, ZrOCl_2·xH_2O, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 2 H (hydrogen) | 4 O (oxygen) | 2 Zr (zirconium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 2 | 35.45 H (hydrogen) | 4 | 1.008 O (oxygen) | 2 | 15.999 Zr (zirconium) | 1 | 91.224 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 Zr (zirconium) | 1 | 91.224 | 1 × 91.224 = 91.224 M = 70.90 g/mol + 4.032 g/mol + 31.998 g/mol + 91.224 g/mol = 198.15 g/mol](../image_source/0c3a4a443dd743e176ac0cdc3375d0f6.png)
Find the molar mass, M, for zirconyl chloride hydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ZrOCl_2·xH_2O Use the chemical formula, ZrOCl_2·xH_2O, to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 2 H (hydrogen) | 4 O (oxygen) | 2 Zr (zirconium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 2 | 35.45 H (hydrogen) | 4 | 1.008 O (oxygen) | 2 | 15.999 Zr (zirconium) | 1 | 91.224 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 Zr (zirconium) | 1 | 91.224 | 1 × 91.224 = 91.224 M = 70.90 g/mol + 4.032 g/mol + 31.998 g/mol + 91.224 g/mol = 198.15 g/mol
Unit conversion
![0.1982 kg/mol (kilograms per mole)](../image_source/347c79ec595b8f1ae5e667f5ab2740fd.png)
0.1982 kg/mol (kilograms per mole)
Comparisons
![≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/009382335adef06d4744d218d86da96c.png)
≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ molar mass of caffeine ( ≈ 194 g/mol )](../image_source/4ed085628ae53caf12a1850208207afb.png)
≈ molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/244321540164f56dda6e5e05c77c1918.png)
≈ 3.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.3×10^-22 grams | 3.3×10^-25 kg (kilograms) | 198 u (unified atomic mass units) | 198 Da (daltons)](../image_source/5e39b3104fa1923e841332cdcefecdf1.png)
Mass of a molecule m from m = M/N_A: | 3.3×10^-22 grams | 3.3×10^-25 kg (kilograms) | 198 u (unified atomic mass units) | 198 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 198](../image_source/67267f00c7d299416c78e64384fc1d8c.png)
Relative molecular mass M_r from M_r = M_u/M: | 198