HCl + Zn + Na2MoO4 = H2O + NaCl + ZnCl2 + Mo9O14

HCl hydrogen chloride + Zn zinc + Na_2MoO_4 sodium molybdate ⟶ H_2O water + NaCl sodium chloride + ZnCl_2 zinc chloride + Mo9O14

Balance the chemical equation algebraically: HCl + Zn + Na_2MoO_4 ⟶ H_2O + NaCl + ZnCl_2 + Mo9O14 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HCl + c_2 Zn + c_3 Na_2MoO_4 ⟶ c_4 H_2O + c_5 NaCl + c_6 ZnCl_2 + c_7 Mo9O14 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, Zn, Mo, Na and O: Cl: | c_1 = c_5 + 2 c_6 H: | c_1 = 2 c_4 Zn: | c_2 = c_6 Mo: | c_3 = 9 c_7 Na: | 2 c_3 = c_5 O: | 4 c_3 = c_4 + 14 c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_7 = 1 and solve the system of equations for the remaining coefficients: c_1 = 44 c_2 = 13 c_3 = 9 c_4 = 22 c_5 = 18 c_6 = 13 c_7 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 44 HCl + 13 Zn + 9 Na_2MoO_4 ⟶ 22 H_2O + 18 NaCl + 13 ZnCl_2 + Mo9O14

+ + ⟶ + + + Mo9O14

hydrogen chloride + zinc + sodium molybdate ⟶ water + sodium chloride + zinc chloride + Mo9O14

K_c = ([H2O]^22 [NaCl]^18 [ZnCl2]^13 [Mo9O14])/([HCl]^44 [Zn]^13 [Na2MoO4]^9)

rate = -1/44 (Δ[HCl])/(Δt) = -1/13 (Δ[Zn])/(Δt) = -1/9 (Δ[Na2MoO4])/(Δt) = 1/22 (Δ[H2O])/(Δt) = 1/18 (Δ[NaCl])/(Δt) = 1/13 (Δ[ZnCl2])/(Δt) = (Δ[Mo9O14])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| hydrogen chloride | zinc | sodium molybdate | water | sodium chloride | zinc chloride | Mo9O14 formula | HCl | Zn | Na_2MoO_4 | H_2O | NaCl | ZnCl_2 | Mo9O14 Hill formula | ClH | Zn | MoNa_2O_4 | H_2O | ClNa | Cl_2Zn | Mo9O14 name | hydrogen chloride | zinc | sodium molybdate | water | sodium chloride | zinc chloride | IUPAC name | hydrogen chloride | zinc | disodium dioxido-dioxomolybdenum | water | sodium chloride | zinc dichloride |