Input interpretation
bismuth(III) iodide | molar mass
Result
Find the molar mass, M, for bismuth(III) iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: BiI_3 Use the chemical formula to count the number of atoms, N_i, for each element: | number of atoms Bi (bismuth) | 1 I (iodine) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | number of atoms | atomic mass/g·mol^(-1) Bi (bismuth) | 1 | 208.98040 I (iodine) | 3 | 126.90447 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | number of atoms | atomic mass/g·mol^(-1) | mass/g·mol^(-1) Bi (bismuth) | 1 | 208.98040 | 1 × 208.98040 = 208.98040 I (iodine) | 3 | 126.90447 | 3 × 126.90447 = 380.71341 M = 208.98040 g/mol + 380.71341 g/mol = 589.69381 g/mol
Unit conversion
0.58969381 kg/mol (kilograms per mole)
Comparisons
≈ 0.82 × molar mass of fullerene (≈ 721 g/mol )
≈ 3 × molar mass of caffeine (≈ 194 g/mol )
≈ 10 × molar mass of sodium chloride (≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 9.8×10^-22 grams | 9.8×10^-25 kg (kilograms) | 590 u (unified atomic mass units) | 590 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 590