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molar mass of 3,3,4,4,5,5,6,6,7,7,8,8,8-tridecafluorooctyl methacrylate

Input interpretation

3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8-tridecafluorooctyl methacrylate | molar mass
3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8-tridecafluorooctyl methacrylate | molar mass

Result

Find the molar mass, M, for 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8-tridecafluorooctyl methacrylate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_12H_9F_13O_2 Use the chemical formula, C_12H_9F_13O_2, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 12  O (oxygen) | 2  F (fluorine) | 13  H (hydrogen) | 9 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 12 | 12.011  O (oxygen) | 2 | 15.999  F (fluorine) | 13 | 18.998403163  H (hydrogen) | 9 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132  O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998  F (fluorine) | 13 | 18.998403163 | 13 × 18.998403163 = 246.979241119  H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072  M = 144.132 g/mol + 31.998 g/mol + 246.979241119 g/mol + 9.072 g/mol = 432.181 g/mol
Find the molar mass, M, for 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8-tridecafluorooctyl methacrylate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_12H_9F_13O_2 Use the chemical formula, C_12H_9F_13O_2, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 O (oxygen) | 2 F (fluorine) | 13 H (hydrogen) | 9 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 O (oxygen) | 2 | 15.999 F (fluorine) | 13 | 18.998403163 H (hydrogen) | 9 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 F (fluorine) | 13 | 18.998403163 | 13 × 18.998403163 = 246.979241119 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 M = 144.132 g/mol + 31.998 g/mol + 246.979241119 g/mol + 9.072 g/mol = 432.181 g/mol

Unit conversion

0.4322 kg/mol (kilograms per mole)
0.4322 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.6 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.6 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 7.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 7.4 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 7.2×10^-22 grams  | 7.2×10^-25 kg (kilograms)  | 432 u (unified atomic mass units)  | 432 Da (daltons)
Mass of a molecule m from m = M/N_A: | 7.2×10^-22 grams | 7.2×10^-25 kg (kilograms) | 432 u (unified atomic mass units) | 432 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 432
Relative molecular mass M_r from M_r = M_u/M: | 432