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HNO3 + HI = H2O + I2 + NO

Input interpretation

HNO_3 (nitric acid) + HI (hydrogen iodide) ⟶ H_2O (water) + I_2 (iodine) + NO (nitric oxide)
HNO_3 (nitric acid) + HI (hydrogen iodide) ⟶ H_2O (water) + I_2 (iodine) + NO (nitric oxide)

Balanced equation

Balance the chemical equation algebraically: HNO_3 + HI ⟶ H_2O + I_2 + NO Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HNO_3 + c_2 HI ⟶ c_3 H_2O + c_4 I_2 + c_5 NO Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and I: H: | c_1 + c_2 = 2 c_3 N: | c_1 = c_5 O: | 3 c_1 = c_3 + c_5 I: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3 c_3 = 2 c_4 = 3/2 c_5 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 2 c_2 = 6 c_3 = 4 c_4 = 3 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 HNO_3 + 6 HI ⟶ 4 H_2O + 3 I_2 + 2 NO
Balance the chemical equation algebraically: HNO_3 + HI ⟶ H_2O + I_2 + NO Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HNO_3 + c_2 HI ⟶ c_3 H_2O + c_4 I_2 + c_5 NO Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and I: H: | c_1 + c_2 = 2 c_3 N: | c_1 = c_5 O: | 3 c_1 = c_3 + c_5 I: | c_2 = 2 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3 c_3 = 2 c_4 = 3/2 c_5 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 2 c_2 = 6 c_3 = 4 c_4 = 3 c_5 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HNO_3 + 6 HI ⟶ 4 H_2O + 3 I_2 + 2 NO

Structures

 + ⟶ + +
+ ⟶ + +

Names

nitric acid + hydrogen iodide ⟶ water + iodine + nitric oxide
nitric acid + hydrogen iodide ⟶ water + iodine + nitric oxide

Reaction thermodynamics

Gibbs free energy

 | nitric acid | hydrogen iodide | water | iodine | nitric oxide molecular free energy | -80.7 kJ/mol | 1.7 kJ/mol | -237.1 kJ/mol | 0 kJ/mol | 87.6 kJ/mol total free energy | -161.4 kJ/mol | 10.2 kJ/mol | -948.4 kJ/mol | 0 kJ/mol | 175.2 kJ/mol  | G_initial = -151.2 kJ/mol | | G_final = -773.2 kJ/mol | |  ΔG_rxn^0 | -773.2 kJ/mol - -151.2 kJ/mol = -622 kJ/mol (exergonic) | | | |
| nitric acid | hydrogen iodide | water | iodine | nitric oxide molecular free energy | -80.7 kJ/mol | 1.7 kJ/mol | -237.1 kJ/mol | 0 kJ/mol | 87.6 kJ/mol total free energy | -161.4 kJ/mol | 10.2 kJ/mol | -948.4 kJ/mol | 0 kJ/mol | 175.2 kJ/mol | G_initial = -151.2 kJ/mol | | G_final = -773.2 kJ/mol | | ΔG_rxn^0 | -773.2 kJ/mol - -151.2 kJ/mol = -622 kJ/mol (exergonic) | | | |

Equilibrium constant

Construct the equilibrium constant, K, expression for: HNO_3 + HI ⟶ H_2O + I_2 + NO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HNO_3 + 6 HI ⟶ 4 H_2O + 3 I_2 + 2 NO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 HI | 6 | -6 H_2O | 4 | 4 I_2 | 3 | 3 NO | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HNO_3 | 2 | -2 | ([HNO3])^(-2) HI | 6 | -6 | ([HI])^(-6) H_2O | 4 | 4 | ([H2O])^4 I_2 | 3 | 3 | ([I2])^3 NO | 2 | 2 | ([NO])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([HNO3])^(-2) ([HI])^(-6) ([H2O])^4 ([I2])^3 ([NO])^2 = (([H2O])^4 ([I2])^3 ([NO])^2)/(([HNO3])^2 ([HI])^6)
Construct the equilibrium constant, K, expression for: HNO_3 + HI ⟶ H_2O + I_2 + NO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HNO_3 + 6 HI ⟶ 4 H_2O + 3 I_2 + 2 NO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 HI | 6 | -6 H_2O | 4 | 4 I_2 | 3 | 3 NO | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HNO_3 | 2 | -2 | ([HNO3])^(-2) HI | 6 | -6 | ([HI])^(-6) H_2O | 4 | 4 | ([H2O])^4 I_2 | 3 | 3 | ([I2])^3 NO | 2 | 2 | ([NO])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HNO3])^(-2) ([HI])^(-6) ([H2O])^4 ([I2])^3 ([NO])^2 = (([H2O])^4 ([I2])^3 ([NO])^2)/(([HNO3])^2 ([HI])^6)

Rate of reaction

Construct the rate of reaction expression for: HNO_3 + HI ⟶ H_2O + I_2 + NO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HNO_3 + 6 HI ⟶ 4 H_2O + 3 I_2 + 2 NO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 HI | 6 | -6 H_2O | 4 | 4 I_2 | 3 | 3 NO | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HNO_3 | 2 | -2 | -1/2 (Δ[HNO3])/(Δt) HI | 6 | -6 | -1/6 (Δ[HI])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) I_2 | 3 | 3 | 1/3 (Δ[I2])/(Δt) NO | 2 | 2 | 1/2 (Δ[NO])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[HNO3])/(Δt) = -1/6 (Δ[HI])/(Δt) = 1/4 (Δ[H2O])/(Δt) = 1/3 (Δ[I2])/(Δt) = 1/2 (Δ[NO])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: HNO_3 + HI ⟶ H_2O + I_2 + NO Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HNO_3 + 6 HI ⟶ 4 H_2O + 3 I_2 + 2 NO Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 HI | 6 | -6 H_2O | 4 | 4 I_2 | 3 | 3 NO | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HNO_3 | 2 | -2 | -1/2 (Δ[HNO3])/(Δt) HI | 6 | -6 | -1/6 (Δ[HI])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) I_2 | 3 | 3 | 1/3 (Δ[I2])/(Δt) NO | 2 | 2 | 1/2 (Δ[NO])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[HNO3])/(Δt) = -1/6 (Δ[HI])/(Δt) = 1/4 (Δ[H2O])/(Δt) = 1/3 (Δ[I2])/(Δt) = 1/2 (Δ[NO])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | nitric acid | hydrogen iodide | water | iodine | nitric oxide formula | HNO_3 | HI | H_2O | I_2 | NO name | nitric acid | hydrogen iodide | water | iodine | nitric oxide IUPAC name | nitric acid | hydrogen iodide | water | molecular iodine | nitric oxide
| nitric acid | hydrogen iodide | water | iodine | nitric oxide formula | HNO_3 | HI | H_2O | I_2 | NO name | nitric acid | hydrogen iodide | water | iodine | nitric oxide IUPAC name | nitric acid | hydrogen iodide | water | molecular iodine | nitric oxide