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HNO3 + PbS = H2O + S + NO + Pb(NO3)2

Input interpretation

nitric acid + lead sulfide ⟶ water + mixed sulfur + nitric oxide + lead(II) nitrate
nitric acid + lead sulfide ⟶ water + mixed sulfur + nitric oxide + lead(II) nitrate

Balanced equation

Balance the chemical equation algebraically:  + ⟶ + + +  Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6  Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Pb and S: H: | c_1 = 2 c_3 N: | c_1 = c_5 + 2 c_6 O: | 3 c_1 = c_3 + c_5 + 6 c_6 Pb: | c_2 = c_6 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 3/2 c_3 = 2 c_4 = 3/2 c_5 = 1 c_6 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 8 c_2 = 3 c_3 = 4 c_4 = 3 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 8 + 3 ⟶ 4 + 3 + 2 + 3
Balance the chemical equation algebraically: + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Pb and S: H: | c_1 = 2 c_3 N: | c_1 = c_5 + 2 c_6 O: | 3 c_1 = c_3 + c_5 + 6 c_6 Pb: | c_2 = c_6 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 3/2 c_3 = 2 c_4 = 3/2 c_5 = 1 c_6 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 8 c_2 = 3 c_3 = 4 c_4 = 3 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 + 3 ⟶ 4 + 3 + 2 + 3

Structures

 + ⟶ + + +
+ ⟶ + + +

Names

nitric acid + lead sulfide ⟶ water + mixed sulfur + nitric oxide + lead(II) nitrate
nitric acid + lead sulfide ⟶ water + mixed sulfur + nitric oxide + lead(II) nitrate

Chemical names and formulas

 | nitric acid | lead sulfide | water | mixed sulfur | nitric oxide | lead(II) nitrate Hill formula | HNO_3 | PbS | H_2O | S | NO | N_2O_6Pb name | nitric acid | lead sulfide | water | mixed sulfur | nitric oxide | lead(II) nitrate IUPAC name | nitric acid | | water | sulfur | nitric oxide | plumbous dinitrate
| nitric acid | lead sulfide | water | mixed sulfur | nitric oxide | lead(II) nitrate Hill formula | HNO_3 | PbS | H_2O | S | NO | N_2O_6Pb name | nitric acid | lead sulfide | water | mixed sulfur | nitric oxide | lead(II) nitrate IUPAC name | nitric acid | | water | sulfur | nitric oxide | plumbous dinitrate