Input interpretation
![nitric acid + lead sulfide ⟶ water + mixed sulfur + nitric oxide + lead(II) nitrate](../image_source/826f86e492357c8ae323bb5f3d25dffe.png)
nitric acid + lead sulfide ⟶ water + mixed sulfur + nitric oxide + lead(II) nitrate
Balanced equation
![Balance the chemical equation algebraically: + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Pb and S: H: | c_1 = 2 c_3 N: | c_1 = c_5 + 2 c_6 O: | 3 c_1 = c_3 + c_5 + 6 c_6 Pb: | c_2 = c_6 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 3/2 c_3 = 2 c_4 = 3/2 c_5 = 1 c_6 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 8 c_2 = 3 c_3 = 4 c_4 = 3 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 + 3 ⟶ 4 + 3 + 2 + 3](../image_source/f4d50de45f300ddd23e0c84bb08dee9a.png)
Balance the chemical equation algebraically: + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 + c_6 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Pb and S: H: | c_1 = 2 c_3 N: | c_1 = c_5 + 2 c_6 O: | 3 c_1 = c_3 + c_5 + 6 c_6 Pb: | c_2 = c_6 S: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 3/2 c_3 = 2 c_4 = 3/2 c_5 = 1 c_6 = 3/2 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 8 c_2 = 3 c_3 = 4 c_4 = 3 c_5 = 2 c_6 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 + 3 ⟶ 4 + 3 + 2 + 3
Structures
![+ ⟶ + + +](../image_source/3e24b6e5f0ec2db4e3f56f4c3ba01b3e.png)
+ ⟶ + + +
Names
![nitric acid + lead sulfide ⟶ water + mixed sulfur + nitric oxide + lead(II) nitrate](../image_source/16363d1cd2067d030bd8f7a2b1d912a2.png)
nitric acid + lead sulfide ⟶ water + mixed sulfur + nitric oxide + lead(II) nitrate
Chemical names and formulas
![| nitric acid | lead sulfide | water | mixed sulfur | nitric oxide | lead(II) nitrate Hill formula | HNO_3 | PbS | H_2O | S | NO | N_2O_6Pb name | nitric acid | lead sulfide | water | mixed sulfur | nitric oxide | lead(II) nitrate IUPAC name | nitric acid | | water | sulfur | nitric oxide | plumbous dinitrate](../image_source/71bb8d587f8f69c14fc8fa62c40c8454.png)
| nitric acid | lead sulfide | water | mixed sulfur | nitric oxide | lead(II) nitrate Hill formula | HNO_3 | PbS | H_2O | S | NO | N_2O_6Pb name | nitric acid | lead sulfide | water | mixed sulfur | nitric oxide | lead(II) nitrate IUPAC name | nitric acid | | water | sulfur | nitric oxide | plumbous dinitrate