Input interpretation
cyanate anion | structure diagram
Result
Draw the Lewis structure of cyanate anion. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the carbon (n_C, val = 4), nitrogen (n_N, val = 5), and oxygen (n_O, val = 6) atoms, including the net charge: n_C, val + n_N, val + n_O, val - n_charge = 16 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), nitrogen (n_N, full = 8), and oxygen (n_O, full = 8): n_C, full + n_N, full + n_O, full = 24 Subtracting these two numbers shows that 24 - 16 = 8 bonding electrons are needed. Each bond has two electrons, so in addition to the 2 bonds already present in the diagram add 2 bonds. To minimize formal charge oxygen wants 2 bonds, nitrogen wants 3 bonds, and carbon wants 4 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom. The net charge has been given to the most electronegative atom, oxygen: Fill in the 2 bonds by pairing electrons between adjacent highlighted atoms, noting the formal charges of the atoms: Answer: | |