Input interpretation
trichloro(pentamethylcyclopentadienyl)titanium(iv) | molar mass
Result
Find the molar mass, M, for trichloro(pentamethylcyclopentadienyl)titanium(iv): M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_10H_15Cl_3Ti Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 3 Ti (titanium) | 1 C (carbon) | 10 H (hydrogen) | 15 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 3 | 35.45 Ti (titanium) | 1 | 47.867 C (carbon) | 10 | 12.011 H (hydrogen) | 15 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 3 | 35.45 | 3 × 35.45 = 106.35 Ti (titanium) | 1 | 47.867 | 1 × 47.867 = 47.867 C (carbon) | 10 | 12.011 | 10 × 12.011 = 120.110 H (hydrogen) | 15 | 1.008 | 15 × 1.008 = 15.120 M = 106.35 g/mol + 47.867 g/mol + 120.110 g/mol + 15.120 g/mol = 289.45 g/mol
Unit conversion
0.2895 kg/mol (kilograms per mole)
Comparisons
≈ 0.4 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms) | 289 u (unified atomic mass units) | 289 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 289