Input interpretation
![sodium periodate trihydrate | molar mass](../image_source/878de0ad9747407b2319ff5911452ca9.png)
sodium periodate trihydrate | molar mass
Result
![Find the molar mass, M, for sodium periodate trihydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NaIO_4·3H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 6 I (iodine) | 1 Na (sodium) | 1 O (oxygen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 6 | 1.008 I (iodine) | 1 | 126.90447 Na (sodium) | 1 | 22.98976928 O (oxygen) | 7 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 M = 6.048 g/mol + 126.90447 g/mol + 22.98976928 g/mol + 111.993 g/mol = 267.935 g/mol](../image_source/2fc4514fa88103233309026534dadfca.png)
Find the molar mass, M, for sodium periodate trihydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: NaIO_4·3H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 6 I (iodine) | 1 Na (sodium) | 1 O (oxygen) | 7 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 6 | 1.008 I (iodine) | 1 | 126.90447 Na (sodium) | 1 | 22.98976928 O (oxygen) | 7 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 Na (sodium) | 1 | 22.98976928 | 1 × 22.98976928 = 22.98976928 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 M = 6.048 g/mol + 126.90447 g/mol + 22.98976928 g/mol + 111.993 g/mol = 267.935 g/mol
Unit conversion
![0.26794 kg/mol (kilograms per mole)](../image_source/339af4b0362d4b3f168739e080b8c629.png)
0.26794 kg/mol (kilograms per mole)
Comparisons
![≈ 0.37 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/206eb533c2ec929ee3ff8fa2674fe461.png)
≈ 0.37 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/8c91808534c9ccdf2c4b04f8bc3ef59d.png)
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.6 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/e18b22f989118e156c4aa5222e146993.png)
≈ 4.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.4×10^-22 grams | 4.4×10^-25 kg (kilograms) | 268 u (unified atomic mass units) | 268 Da (daltons)](../image_source/df015e485ca3095d11e3f293a88609f7.png)
Mass of a molecule m from m = M/N_A: | 4.4×10^-22 grams | 4.4×10^-25 kg (kilograms) | 268 u (unified atomic mass units) | 268 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 268](../image_source/30756627ef0f5e9fbed60995751be804.png)
Relative molecular mass M_r from M_r = M_u/M: | 268