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FeCl3 + NaF = NaCl + FeF3

Input interpretation

FeCl_3 iron(III) chloride + NaF sodium fluoride ⟶ NaCl sodium chloride + FeF_3 ferric fluoride
FeCl_3 iron(III) chloride + NaF sodium fluoride ⟶ NaCl sodium chloride + FeF_3 ferric fluoride

Balanced equation

Balance the chemical equation algebraically: FeCl_3 + NaF ⟶ NaCl + FeF_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 FeCl_3 + c_2 NaF ⟶ c_3 NaCl + c_4 FeF_3 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, Fe, F and Na: Cl: | 3 c_1 = c_3 Fe: | c_1 = c_4 F: | c_2 = 3 c_4 Na: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | FeCl_3 + 3 NaF ⟶ 3 NaCl + FeF_3
Balance the chemical equation algebraically: FeCl_3 + NaF ⟶ NaCl + FeF_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 FeCl_3 + c_2 NaF ⟶ c_3 NaCl + c_4 FeF_3 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, Fe, F and Na: Cl: | 3 c_1 = c_3 Fe: | c_1 = c_4 F: | c_2 = 3 c_4 Na: | c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | FeCl_3 + 3 NaF ⟶ 3 NaCl + FeF_3

Structures

+ ⟶ +
+ ⟶ +

Names

iron(III) chloride + sodium fluoride ⟶ sodium chloride + ferric fluoride
iron(III) chloride + sodium fluoride ⟶ sodium chloride + ferric fluoride

Equilibrium constant

Construct the equilibrium constant, K, expression for: FeCl_3 + NaF ⟶ NaCl + FeF_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: FeCl_3 + 3 NaF ⟶ 3 NaCl + FeF_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i FeCl_3 | 1 | -1 NaF | 3 | -3 NaCl | 3 | 3 FeF_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression FeCl_3 | 1 | -1 | ([FeCl3])^(-1) NaF | 3 | -3 | ([NaF])^(-3) NaCl | 3 | 3 | ([NaCl])^3 FeF_3 | 1 | 1 | [FeF3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([FeCl3])^(-1) ([NaF])^(-3) ([NaCl])^3 [FeF3] = (([NaCl])^3 [FeF3])/([FeCl3] ([NaF])^3)
Construct the equilibrium constant, K, expression for: FeCl_3 + NaF ⟶ NaCl + FeF_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: FeCl_3 + 3 NaF ⟶ 3 NaCl + FeF_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i FeCl_3 | 1 | -1 NaF | 3 | -3 NaCl | 3 | 3 FeF_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression FeCl_3 | 1 | -1 | ([FeCl3])^(-1) NaF | 3 | -3 | ([NaF])^(-3) NaCl | 3 | 3 | ([NaCl])^3 FeF_3 | 1 | 1 | [FeF3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([FeCl3])^(-1) ([NaF])^(-3) ([NaCl])^3 [FeF3] = (([NaCl])^3 [FeF3])/([FeCl3] ([NaF])^3)

Rate of reaction

Construct the rate of reaction expression for: FeCl_3 + NaF ⟶ NaCl + FeF_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: FeCl_3 + 3 NaF ⟶ 3 NaCl + FeF_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i FeCl_3 | 1 | -1 NaF | 3 | -3 NaCl | 3 | 3 FeF_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term FeCl_3 | 1 | -1 | -(Δ[FeCl3])/(Δt) NaF | 3 | -3 | -1/3 (Δ[NaF])/(Δt) NaCl | 3 | 3 | 1/3 (Δ[NaCl])/(Δt) FeF_3 | 1 | 1 | (Δ[FeF3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[FeCl3])/(Δt) = -1/3 (Δ[NaF])/(Δt) = 1/3 (Δ[NaCl])/(Δt) = (Δ[FeF3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: FeCl_3 + NaF ⟶ NaCl + FeF_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: FeCl_3 + 3 NaF ⟶ 3 NaCl + FeF_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i FeCl_3 | 1 | -1 NaF | 3 | -3 NaCl | 3 | 3 FeF_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term FeCl_3 | 1 | -1 | -(Δ[FeCl3])/(Δt) NaF | 3 | -3 | -1/3 (Δ[NaF])/(Δt) NaCl | 3 | 3 | 1/3 (Δ[NaCl])/(Δt) FeF_3 | 1 | 1 | (Δ[FeF3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[FeCl3])/(Δt) = -1/3 (Δ[NaF])/(Δt) = 1/3 (Δ[NaCl])/(Δt) = (Δ[FeF3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| iron(III) chloride | sodium fluoride | sodium chloride | ferric fluoride formula | FeCl_3 | NaF | NaCl | FeF_3 Hill formula | Cl_3Fe | FNa | ClNa | F_3Fe name | iron(III) chloride | sodium fluoride | sodium chloride | ferric fluoride IUPAC name | trichloroiron | sodium fluoride | sodium chloride | trifluoroiron
| iron(III) chloride | sodium fluoride | sodium chloride | ferric fluoride formula | FeCl_3 | NaF | NaCl | FeF_3 Hill formula | Cl_3Fe | FNa | ClNa | F_3Fe name | iron(III) chloride | sodium fluoride | sodium chloride | ferric fluoride IUPAC name | trichloroiron | sodium fluoride | sodium chloride | trifluoroiron

Substance properties

| iron(III) chloride | sodium fluoride | sodium chloride | ferric fluoride molar mass | 162.2 g/mol | 41.98817244 g/mol | 58.44 g/mol | 112.84 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | solid (at STP) melting point | 304 °C | 993 °C | 801 °C | 1000 °C boiling point | | 1700 °C | 1413 °C | density | | 2.558 g/cm^3 | 2.16 g/cm^3 | 3.52 g/cm^3 solubility in water | | | soluble | slightly soluble dynamic viscosity | | 0.00105 Pa s (at 1160 °C) | | odor | | odorless | odorless |
| iron(III) chloride | sodium fluoride | sodium chloride | ferric fluoride molar mass | 162.2 g/mol | 41.98817244 g/mol | 58.44 g/mol | 112.84 g/mol phase | solid (at STP) | solid (at STP) | solid (at STP) | solid (at STP) melting point | 304 °C | 993 °C | 801 °C | 1000 °C boiling point | | 1700 °C | 1413 °C | density | | 2.558 g/cm^3 | 2.16 g/cm^3 | 3.52 g/cm^3 solubility in water | | | soluble | slightly soluble dynamic viscosity | | 0.00105 Pa s (at 1160 °C) | | odor | | odorless | odorless |

Units

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